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How many grams of sodium hydroxide are required to dissolve in 232 g of water to make a 2 .88 m solution? NaOH:39.99g/mol [?]gNaOH

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Joseph Hendricks Master · Tutor for 5 years

Answer

26.72 g NaOH

Explanation

1. Understand Molality Formula Molality (m) is defined as moles of solute per kilogram of solvent. **Molality = \frac{\text{moles of solute}}{\text{kg of solvent}}**2. Convert Solvent Mass to Kilograms 232 g of water is equivalent to 0.232 kg.3. Calculate Moles of NaOH Required Using the molality formula: . Therefore, moles of NaOH = .4. Calculate Grams of NaOH Moles of NaOH = . Grams of NaOH = moles molar mass = .