That previous shot was a bust and the player tries for a second shot. This time they throw the ball at 8m/s with a 45 degree angle. The height of the throw is 2.4 m above the floor and the hoop is 3.1 m tall. How long will the ball be in the air before reaching the height of the hoop? (hint:we've done this in examples and there are two ways of doing it) 8.11 sec 0.63 sec 0.12 sec 1.01 sec 1.35 sec 5.31 sec

1. Break velocity into components 2. Use vertical motion equation Formula: ** ** We set , , , : 3. Rearrange equation 4. Solve quadratic 5. Select positive times Only upward time to hoop is relevant for first hit → }