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How many moles of NaOH are needed to neutralize 15.0 mL of 0.235 M HCl solution? Hints: Don't forget to write the equation, balance it, and make sure units of volume are consistant 0.00353 moles 35.3 moles 0.235 moles 3.53 moles 23.5 moles 2.35 moles

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4.6 (211 Votes)
Edwina Glover Master · Tutor for 5 years

Answer

0.00353 moles

Explanation

1. Write and Balance the Equation The neutralization reaction is . It is already balanced.2. Calculate Moles of HCl Use the formula ** **, where is moles, is concentration (0.235 M), and is volume in liters (15.0 mL = 0.015 L). So, moles of HCl.3. Determine Moles of NaOH Needed From the balanced equation, 1 mole of NaOH reacts with 1 mole of HCl. Therefore, 0.003525 moles of NaOH are needed.