QuestionMay 12, 2025

underline (2)H_(2)(g)+O_(2)(g)arrow underline (2)H_(2)O(g) How many liters of water can be made from 5 L of oxygen gas and excess hydrogen gas at STP?

underline (2)H_(2)(g)+O_(2)(g)arrow underline (2)H_(2)O(g) How many liters of water can be made from 5 L of oxygen gas and excess hydrogen gas at STP?
underline (2)H_(2)(g)+O_(2)(g)arrow underline (2)H_(2)O(g)
How many liters of water can be made from 5 L of oxygen gas and excess hydrogen gas at STP?

Solution
4.2(178 votes)

Answer

10 liters of water can be made. Explanation 1. Determine the molar ratio from the balanced equation From the equation, 2H_2 + O_2 \rightarrow 2H_2O, the molar ratio of O_2 to H_2O is 1:2. 2. Apply the gas law relationship at STP At STP, equal volumes of gases have equal moles. Thus, 5 L of O_2 produces 2 \times 5 = 10 L of H_2O.

Explanation

1. Determine the molar ratio from the balanced equation<br /> From the equation, $2H_2 + O_2 \rightarrow 2H_2O$, the molar ratio of $O_2$ to $H_2O$ is $1:2$.<br /><br />2. Apply the gas law relationship at STP<br /> At STP, equal volumes of gases have equal moles. Thus, 5 L of $O_2$ produces $2 \times 5 = 10$ L of $H_2O$.
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