QuestionMay 14, 2025

19. How many moles are present in 20.0 g of NO_(2)

19. How many moles are present in 20.0 g of NO_(2)
19. How many moles are present in 20.0 g
of NO_(2)

Solution
4.2(315 votes)

Answer

0.435 moles Explanation 1. Calculate Molar Mass of NO_2 Molar mass of N = 14.01 \, \text{g/mol}; molar mass of O = 16.00 \, \text{g/mol}. For NO_2, molar mass = 14.01 + 2 \times 16.00 = 46.01 \, \text{g/mol}. 2. Calculate Moles Use formula: **n = \frac{\text{mass}}{\text{molar mass}}**. Substitute values: n = \frac{20.0}{46.01}.

Explanation

1. Calculate Molar Mass of $NO_2$<br /> Molar mass of $N = 14.01 \, \text{g/mol}$; molar mass of $O = 16.00 \, \text{g/mol}$. For $NO_2$, molar mass = $14.01 + 2 \times 16.00 = 46.01 \, \text{g/mol}$.<br />2. Calculate Moles<br /> Use formula: **$n = \frac{\text{mass}}{\text{molar mass}}$**. Substitute values: $n = \frac{20.0}{46.01}$.
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