QuestionMay 4, 2025

1. How many calories are required to increase the temperature of 13.0 g of ethanol from -11.0^circ C to 23.6^circ C ? The specific heat of ethanol is 2.46J/g^circ C 1110 cal 403 cal 264 cal 96.3.9 cal

1. How many calories are required to increase the temperature of 13.0 g of ethanol from -11.0^circ C to 23.6^circ C ? The specific heat of ethanol is 2.46J/g^circ C 1110 cal 403 cal 264 cal 96.3.9 cal
1. How many calories are required to increase the temperature of 13.0 g of
ethanol from -11.0^circ C to 23.6^circ C ? The specific heat of ethanol is 2.46J/g^circ C
1110 cal
403 cal
264 cal
96.3.9 cal

Solution
4.1(254 votes)

Answer

264 cal Explanation 1. Convert specific heat to calories 1 calorie = 4.184 joules. Convert 2.46 \, J/g^{\circ}C to calories: 2.46 \, J/g^{\circ}C \div 4.184 = 0.588 \, cal/g^{\circ}C. 2. Calculate temperature change \Delta T = T_{\text{final}} - T_{\text{initial}} = 23.6 - (-11.0) = 34.6^{\circ}C. 3. Apply heat formula Use q = m \cdot c \cdot \Delta T: q = 13.0 \, g \cdot 0.588 \, cal/g^{\circ}C \cdot 34.6^{\circ}C = 264.5 \, cal.

Explanation

1. Convert specific heat to calories<br /> 1 calorie = 4.184 joules. Convert $2.46 \, J/g^{\circ}C$ to calories: <br />$2.46 \, J/g^{\circ}C \div 4.184 = 0.588 \, cal/g^{\circ}C$.<br /><br />2. Calculate temperature change<br /> $\Delta T = T_{\text{final}} - T_{\text{initial}} = 23.6 - (-11.0) = 34.6^{\circ}C$.<br /><br />3. Apply heat formula<br /> Use $q = m \cdot c \cdot \Delta T$: <br />$q = 13.0 \, g \cdot 0.588 \, cal/g^{\circ}C \cdot 34.6^{\circ}C = 264.5 \, cal$.
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