QuestionJune 27, 2025

What is the acceleration of a train that takes 22 seconds to go from a speed of 73 kilometers per hour to a speed of 45 kilometers per hour? -1.3km/h/s 0.79km/h/s -1.3km/h^2 -1.1km/h/s -1.6km/hs

What is the acceleration of a train that takes 22 seconds to go from a speed of 73 kilometers per hour to a speed of 45 kilometers per hour? -1.3km/h/s 0.79km/h/s -1.3km/h^2 -1.1km/h/s -1.6km/hs
What is the acceleration of a train that takes 22 seconds to go from a speed of 73 kilometers per hour to a
speed of 45 kilometers per hour?
-1.3km/h/s
0.79km/h/s
-1.3km/h^2
-1.1km/h/s
-1.6km/hs

Solution
4.0(201 votes)

Answer

-1.3 \text{ km/h/s} Explanation 1. Convert speeds to consistent units Initial speed v_i = 73 \text{ km/h}, final speed v_f = 45 \text{ km/h}. No conversion needed as the answer is in km/h/s. 2. Calculate acceleration Use the formula **a = \frac{v_f - v_i}{t}** where t = 22 \text{ s}. a = \frac{45 - 73}{22} = \frac{-28}{22} = -1.27 \text{ km/h/s}.

Explanation

1. Convert speeds to consistent units<br /> Initial speed $v_i = 73 \text{ km/h}$, final speed $v_f = 45 \text{ km/h}$. No conversion needed as the answer is in km/h/s.<br />2. Calculate acceleration<br /> Use the formula **$a = \frac{v_f - v_i}{t}$** where $t = 22 \text{ s}$.<br /> $a = \frac{45 - 73}{22} = \frac{-28}{22} = -1.27 \text{ km/h/s}$.
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