QuestionAugust 26, 2025

Solve the inequality algebraically. (5)/(x-5)gt (8)/(3x-3) The solution is square (Simplify your answer. Type your answer i in interval notation. Use integers or fractions for any numbers in the expression.)

Solve the inequality algebraically. (5)/(x-5)gt (8)/(3x-3) The solution is square (Simplify your answer. Type your answer i in interval notation. Use integers or fractions for any numbers in the expression.)
Solve the inequality algebraically.
(5)/(x-5)gt (8)/(3x-3)
The solution is square 
(Simplify your answer. Type your answer i in interval notation. Use integers or fractions for any numbers in the expression.)

Solution
4.7(291 votes)

Answer

(-\frac{25}{7}, 1) \cup (1, 5) \cup (5, \infty) Explanation 1. Find a common denominator The denominators are x-5 and 3x-3. Factor 3x-3 as 3(x-1). The common denominator is (x-5)(3(x-1)). 2. Rewrite the inequality Multiply both sides by the common denominator to eliminate fractions: 5(3(x-1)) > 8(x-5). 3. Expand and simplify Expand both sides: 15x - 15 > 8x - 40. 4. Solve for x Rearrange terms: 15x - 8x > -40 + 15, which simplifies to 7x > -25. 5. Divide by coefficient of x Divide both sides by 7: x > -\frac{25}{7}. 6. Consider domain restrictions Exclude values that make original denominators zero: x \neq 5 and x \neq 1. 7. Write solution in interval notation Combine the solution with domain restrictions: (-\frac{25}{7}, 1) \cup (1, 5) \cup (5, \infty).

Explanation

1. Find a common denominator<br /> The denominators are $x-5$ and $3x-3$. Factor $3x-3$ as $3(x-1)$. The common denominator is $(x-5)(3(x-1))$.<br /><br />2. Rewrite the inequality<br /> Multiply both sides by the common denominator to eliminate fractions: $5(3(x-1)) > 8(x-5)$.<br /><br />3. Expand and simplify<br /> Expand both sides: $15x - 15 > 8x - 40$.<br /><br />4. Solve for x<br /> Rearrange terms: $15x - 8x > -40 + 15$, which simplifies to $7x > -25$.<br /><br />5. Divide by coefficient of x<br /> Divide both sides by 7: $x > -\frac{25}{7}$.<br /><br />6. Consider domain restrictions<br /> Exclude values that make original denominators zero: $x \neq 5$ and $x \neq 1$.<br /><br />7. Write solution in interval notation<br /> Combine the solution with domain restrictions: $(-\frac{25}{7}, 1) \cup (1, 5) \cup (5, \infty)$.
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