QuestionJuly 24, 2025

4PH_(3)arrow P_(4)+6H_(2) In a previous step, you calculated I the rate of disappearance of PH_(3) at 6.67times 10-3M/s What is the rate of appearance of P_(4) in the same time frame? Rate=-(1)/(4)(Delta [PH_(3)])/(Delta t)=(Delta [P_(4)])/(Delta t) Rate_(P_(4))=[?]times 10^[?]M/s Coefficient (green) Exponent (yellow)

4PH_(3)arrow P_(4)+6H_(2) In a previous step, you calculated I the rate of disappearance of PH_(3) at 6.67times 10-3M/s What is the rate of appearance of P_(4) in the same time frame? Rate=-(1)/(4)(Delta [PH_(3)])/(Delta t)=(Delta [P_(4)])/(Delta t) Rate_(P_(4))=[?]times 10^[?]M/s Coefficient (green) Exponent (yellow)
4PH_(3)arrow P_(4)+6H_(2)
In a previous step, you calculated I the rate of
disappearance of PH_(3) at 6.67times 10-3M/s
What is the rate of appearance of P_(4) in the
same time frame?
Rate=-(1)/(4)(Delta [PH_(3)])/(Delta t)=(Delta [P_(4)])/(Delta t)
Rate_(P_(4))=[?]times 10^[?]M/s
Coefficient (green)
Exponent (yellow)

Solution
4.1(207 votes)

Answer

1.67 \times 10^{-3} \text{ M/s} Explanation 1. Identify the relationship between rates The rate of disappearance of PH_3 is related to the rate of appearance of P_4 by stoichiometry. From the equation, 4 moles of PH_3 produce 1 mole of P_4. Therefore, the rate of appearance of P_4 is \frac{1}{4} of the rate of disappearance of PH_3. 2. Calculate the rate of appearance of P_4 Given the rate of disappearance of PH_3 is 6.67 \times 10^{-3} \text{ M/s}, the rate of appearance of P_4 is: Rate_{P_4} = \frac{1}{4} \times 6.67 \times 10^{-3} \text{ M/s}

Explanation

1. Identify the relationship between rates<br /> The rate of disappearance of $PH_3$ is related to the rate of appearance of $P_4$ by stoichiometry. From the equation, 4 moles of $PH_3$ produce 1 mole of $P_4$. Therefore, the rate of appearance of $P_4$ is $\frac{1}{4}$ of the rate of disappearance of $PH_3$.<br /><br />2. Calculate the rate of appearance of $P_4$<br /> Given the rate of disappearance of $PH_3$ is $6.67 \times 10^{-3} \text{ M/s}$, the rate of appearance of $P_4$ is:<br /> $$Rate_{P_4} = \frac{1}{4} \times 6.67 \times 10^{-3} \text{ M/s}$$
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