QuestionJuly 15, 2025

A study determined that 6% of children under 18 years old lived with their father only. Find the probability that none of 15 children, selected at random from all children under 18 years old, lived with their father only. The probability that none of the children lived with their father only is square (Do not round until the final answer. Then round to the nearest thousandth as needed.)

A study determined that 6% of children under 18 years old lived with their father only. Find the probability that none of 15 children, selected at random from all children under 18 years old, lived with their father only. The probability that none of the children lived with their father only is square (Do not round until the final answer. Then round to the nearest thousandth as needed.)
A study determined that 6% 
of children under 18 years old lived with their father only. Find the probability that none of 15 children, selected at random from all children under 18 years old, lived with their
father only.
The probability that none of the children lived with their father only is square 
(Do not round until the final answer. Then round to the nearest thousandth as needed.)

Solution
4.6(300 votes)

Answer

0.418 Explanation 1. Identify the probability of a single event The probability that a child lives with their father only is p = 0.06. 2. Calculate the probability of the complementary event The probability that a child does not live with their father only is 1 - p = 0.94. 3. Apply the binomial probability formula for zero successes Use the formula for the probability of zero successes in n trials: **P(X = 0) = (1-p)^n**. Here, n = 15. 4. Compute the probability Substitute the values: P(X = 0) = (0.94)^{15}.

Explanation

1. Identify the probability of a single event<br /> The probability that a child lives with their father only is $p = 0.06$.<br /><br />2. Calculate the probability of the complementary event<br /> The probability that a child does not live with their father only is $1 - p = 0.94$.<br /><br />3. Apply the binomial probability formula for zero successes<br /> Use the formula for the probability of zero successes in $n$ trials: **$P(X = 0) = (1-p)^n$**. Here, $n = 15$.<br /><br />4. Compute the probability<br /> Substitute the values: $P(X = 0) = (0.94)^{15}$.
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