QuestionJuly 15, 2025

Calculate the change in heat when 10.00 gof water vapor (steam) at 100.0^circ C condenses to liquid water and then cools to 15.00^circ C square J

Calculate the change in heat when 10.00 gof water vapor (steam) at 100.0^circ C condenses to liquid water and then cools to 15.00^circ C square J
Calculate the change in heat when 10.00 gof water vapor (steam) at 100.0^circ C condenses to liquid water and then cools to 15.00^circ C
square  J

Solution
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Answer

26153 J Explanation 1. Calculate heat released during condensation Use q = m \cdot \Delta H_{vap}, where \Delta H_{vap} = 2260 \, \text{J/g} for water. q = 10.00 \, \text{g} \times 2260 \, \text{J/g} = 22600 \, \text{J}. 2. Calculate heat released during cooling Use q = m \cdot c \cdot \Delta T, where c = 4.18 \, \text{J/g}^{\circ}\text{C} for water. \Delta T = 100.0^{\circ}\text{C} - 15.0^{\circ}\text{C} = 85.0^{\circ}\text{C}. q = 10.00 \, \text{g} \times 4.18 \, \text{J/g}^{\circ}\text{C} \times 85.0^{\circ}\text{C} = 3553 \, \text{J}. 3. Sum the total heat change Total heat change = 22600 \, \text{J} + 3553 \, \text{J} = 26153 \, \text{J}.

Explanation

1. Calculate heat released during condensation<br /> Use $q = m \cdot \Delta H_{vap}$, where $\Delta H_{vap} = 2260 \, \text{J/g}$ for water. $q = 10.00 \, \text{g} \times 2260 \, \text{J/g} = 22600 \, \text{J}$.<br />2. Calculate heat released during cooling<br /> Use $q = m \cdot c \cdot \Delta T$, where $c = 4.18 \, \text{J/g}^{\circ}\text{C}$ for water. $\Delta T = 100.0^{\circ}\text{C} - 15.0^{\circ}\text{C} = 85.0^{\circ}\text{C}$. $q = 10.00 \, \text{g} \times 4.18 \, \text{J/g}^{\circ}\text{C} \times 85.0^{\circ}\text{C} = 3553 \, \text{J}$.<br />3. Sum the total heat change<br /> Total heat change $= 22600 \, \text{J} + 3553 \, \text{J} = 26153 \, \text{J}$.
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