QuestionFebruary 2, 2026

D Proot: Because Bis the m midpoint of overline (AC) and square is the midpoint of overline (BD) we know by the square that overline (AB)cong overline (BC) and overline (BC)cong overline (CD) Because congruent segments have square v that Select Choice v/measures. AB=BC and square Thus, by the square AB=CD different

D Proot: Because Bis the m midpoint of overline (AC) and square is the midpoint of overline (BD) we know by the square that overline (AB)cong overline (BC) and overline (BC)cong overline (CD) Because congruent segments have square v that Select Choice v/measures. AB=BC and square Thus, by the square AB=CD different
D Proot: Because Bis the m midpoint of overline (AC) and square is the midpoint of overline (BD) we know by the square that overline (AB)cong overline (BC) and overline (BC)cong overline (CD) Because congruent segments have square v that Select Choice v/measures. AB=BC and square Thus, by the square AB=CD different

Solution
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Answer

\overline{AB} = \overline{CD} Explanation 1. Identify Midpoints Given that B is the midpoint of \overline{AC}, it implies \overline{AB} \cong \overline{BC}. Similarly, if D is the midpoint of \overline{BD}, then \overline{BD} \cong \overline{DC}. 2. Apply Segment Congruence Since B is the midpoint of \overline{AC}, \overline{AB} = \overline{BC}. If D is the midpoint of \overline{BD}, then \overline{BD} = \overline{DC}. 3. Transitive Property of Congruence By the transitive property, if \overline{AB} = \overline{BC} and \overline{BC} = \overline{CD}, then \overline{AB} = \overline{CD}.

Explanation

1. Identify Midpoints<br /> Given that $B$ is the midpoint of $\overline{AC}$, it implies $\overline{AB} \cong \overline{BC}$. Similarly, if $D$ is the midpoint of $\overline{BD}$, then $\overline{BD} \cong \overline{DC}$.<br /><br />2. Apply Segment Congruence<br /> Since $B$ is the midpoint of $\overline{AC}$, $\overline{AB} = \overline{BC}$. If $D$ is the midpoint of $\overline{BD}$, then $\overline{BD} = \overline{DC}$.<br /><br />3. Transitive Property of Congruence<br /> By the transitive property, if $\overline{AB} = \overline{BC}$ and $\overline{BC} = \overline{CD}$, then $\overline{AB} = \overline{CD}$.
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