QuestionJuly 14, 2025

How many grams of KOH would be required to make 2.00L of a 0.50M solution of KOH? 46.1 g 40.1g 56.1g 50.10 g

How many grams of KOH would be required to make 2.00L of a 0.50M solution of KOH? 46.1 g 40.1g 56.1g 50.10 g
How many grams of KOH would be required to make 2.00L of a 0.50M solution of KOH?
46.1 g
40.1g
56.1g
50.10 g

Solution
3.2(338 votes)

Answer

56.1 g Explanation 1. Calculate moles of KOH Use the formula for molarity: M = \frac{\text{moles}}{\text{liters}}. Rearrange to find moles: \text{moles} = M \times \text{liters} = 0.50 \, \text{mol/L} \times 2.00 \, \text{L} = 1.00 \, \text{mol}. 2. Convert moles to grams Use the molar mass of KOH (approximately 56.1 g/mol): \text{grams} = \text{moles} \times \text{molar mass} = 1.00 \, \text{mol} \times 56.1 \, \text{g/mol} = 56.1 \, \text{g}.

Explanation

1. Calculate moles of KOH<br /> Use the formula for molarity: $M = \frac{\text{moles}}{\text{liters}}$. Rearrange to find moles: $\text{moles} = M \times \text{liters} = 0.50 \, \text{mol/L} \times 2.00 \, \text{L} = 1.00 \, \text{mol}$.<br />2. Convert moles to grams<br /> Use the molar mass of KOH (approximately 56.1 g/mol): $\text{grams} = \text{moles} \times \text{molar mass} = 1.00 \, \text{mol} \times 56.1 \, \text{g/mol} = 56.1 \, \text{g}$.
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