QuestionMay 11, 2025

Question 2(Multiple Choice Worth 3 points) (08.02 MC) A 0.420 M Ca(OH)_(2) solution was prepared by dissolving 64.0 grams of Ca(OH)_(2) in enough water.What is the total volume of the solution formed? 1.07 liters 1.23 liters 2.05 liters 2.18 liters

Question 2(Multiple Choice Worth 3 points) (08.02 MC) A 0.420 M Ca(OH)_(2) solution was prepared by dissolving 64.0 grams of Ca(OH)_(2) in enough water.What is the total volume of the solution formed? 1.07 liters 1.23 liters 2.05 liters 2.18 liters
Question 2(Multiple Choice Worth 3 points)
(08.02 MC)
A 0.420 M Ca(OH)_(2) solution was prepared by dissolving
64.0 grams of Ca(OH)_(2) in enough water.What is the
total volume of the solution formed?
1.07 liters
1.23 liters
2.05 liters
2.18 liters

Solution
4.1(296 votes)

Answer

2.05 liters Explanation 1. Calculate moles of Ca(OH)_{2} Molar mass of Ca(OH)_{2} is 40.08 + 2(16.00 + 1.01) = 74.10 g/mol. Moles = \frac{64.0 \text{ g}}{74.10 \text{ g/mol}} = 0.864 mol. 2. Use molarity formula to find volume **Molarity (M) = \frac{\text{moles of solute}}{\text{volume of solution in liters}}**. Rearrange to find volume: Volume = \frac{\text{moles}}{\text{Molarity}} = \frac{0.864 \text{ mol}}{0.420 \text{ M}} = 2.057 L.

Explanation

1. Calculate moles of $Ca(OH)_{2}$<br /> Molar mass of $Ca(OH)_{2}$ is $40.08 + 2(16.00 + 1.01) = 74.10$ g/mol. Moles = $\frac{64.0 \text{ g}}{74.10 \text{ g/mol}} = 0.864$ mol.<br /><br />2. Use molarity formula to find volume<br /> **Molarity (M) = $\frac{\text{moles of solute}}{\text{volume of solution in liters}}$**. Rearrange to find volume: Volume = $\frac{\text{moles}}{\text{Molarity}} = \frac{0.864 \text{ mol}}{0.420 \text{ M}} = 2.057$ L.
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