QuestionMay 15, 2025

Given 0.45 grams of N_(2) how many grams of NaN_(3) are needed? 2NaN_(3)... 2Na+3N_(2) 0.70 g NaN3 0.25 g NaN3 3.0 g NaN3

Given 0.45 grams of N_(2) how many grams of NaN_(3) are needed? 2NaN_(3)... 2Na+3N_(2) 0.70 g NaN3 0.25 g NaN3 3.0 g NaN3
Given 0.45 grams of N_(2) how many grams of NaN_(3) are needed? 2NaN_(3)... 2Na+3N_(2) 0.70 g NaN3 0.25 g NaN3 3.0 g NaN3

Solution
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Answer

0.70 g NaN3 Explanation 1. Calculate moles of N_2 Use the molar mass of N_2 (28.02 g/mol). Moles = \frac{0.45 \text{ g}}{28.02 \text{ g/mol}} = 0.01606 mol. 2. Determine moles of NaN_3 needed From the balanced equation, 3 moles of N_2 are produced from 2 moles of NaN_3. Therefore, moles of NaN_3 = \frac{2}{3} \times 0.01606 mol = 0.01071 mol. 3. Convert moles of NaN_3 to grams Use the molar mass of NaN_3 (65.01 g/mol). Grams = 0.01071 mol \times 65.01 \text{ g/mol} = 0.696 g.

Explanation

1. Calculate moles of $N_2$<br /> Use the molar mass of $N_2$ (28.02 g/mol). Moles = $\frac{0.45 \text{ g}}{28.02 \text{ g/mol}} = 0.01606$ mol.<br /><br />2. Determine moles of $NaN_3$ needed<br /> From the balanced equation, $3$ moles of $N_2$ are produced from $2$ moles of $NaN_3$. Therefore, moles of $NaN_3$ = $\frac{2}{3} \times 0.01606$ mol = $0.01071$ mol.<br /><br />3. Convert moles of $NaN_3$ to grams<br /> Use the molar mass of $NaN_3$ (65.01 g/mol). Grams = $0.01071$ mol $\times 65.01 \text{ g/mol} = 0.696$ g.
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