QuestionMay 15, 2025

8. How many grams of HF are needed to react with 300 grams of sodium silicate? underline ( )Na_(2)SiO_(3)+underline ( )HFarrow underline ( )H_(2)SiF_(6)+underline ( )NaF+underline ( )H_(2)O

8. How many grams of HF are needed to react with 300 grams of sodium silicate? underline ( )Na_(2)SiO_(3)+underline ( )HFarrow underline ( )H_(2)SiF_(6)+underline ( )NaF+underline ( )H_(2)O
8. How many grams of HF are needed to react with 300 grams of sodium silicate? underline ( )Na_(2)SiO_(3)+underline ( )HFarrow underline ( )H_(2)SiF_(6)+underline ( )NaF+underline ( )H_(2)O

Solution
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Answer

295.2 grams of HF are needed. Explanation 1. Determine the molar mass of sodium silicate (Na₂SiO₃) Molar mass of Na₂SiO₃ = 2 \times 23 + 28 + 3 \times 16 = 122 \, \text{g/mol} 2. Calculate moles of sodium silicate Moles of Na₂SiO₃ = \frac{300 \, \text{g}}{122 \, \text{g/mol}} \approx 2.46 \, \text{mol} 3. Use stoichiometry to find moles of HF needed From the balanced equation, 1 mole of Na₂SiO₃ reacts with 6 moles of HF. Moles of HF needed = 2.46 \, \text{mol Na₂SiO₃} \times 6 \, \text{mol HF/mol Na₂SiO₃} = 14.76 \, \text{mol HF} 4. Calculate grams of HF needed Molar mass of HF = 1 + 19 = 20 \, \text{g/mol} Grams of HF = 14.76 \, \text{mol} \times 20 \, \text{g/mol} = 295.2 \, \text{g}

Explanation

1. Determine the molar mass of sodium silicate (Na₂SiO₃)<br /> Molar mass of Na₂SiO₃ = $2 \times 23 + 28 + 3 \times 16 = 122 \, \text{g/mol}$<br />2. Calculate moles of sodium silicate<br /> Moles of Na₂SiO₃ = $\frac{300 \, \text{g}}{122 \, \text{g/mol}} \approx 2.46 \, \text{mol}$<br />3. Use stoichiometry to find moles of HF needed<br /> From the balanced equation, 1 mole of Na₂SiO₃ reacts with 6 moles of HF.<br /> Moles of HF needed = $2.46 \, \text{mol Na₂SiO₃} \times 6 \, \text{mol HF/mol Na₂SiO₃} = 14.76 \, \text{mol HF}$<br />4. Calculate grams of HF needed<br /> Molar mass of HF = $1 + 19 = 20 \, \text{g/mol}$<br /> Grams of HF = $14.76 \, \text{mol} \times 20 \, \text{g/mol} = 295.2 \, \text{g}$
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