If the resistance of the run winding decreases, the __ motor will draw too much current while it is running centrifugal starting switch will not start the motor load on the motor is probably too great motor probably will not start

A beam of light is traveling through a medium at $200,000km/s.$ It enters a different medium and speeds up to almost $250,000km/s$ Finally, it enters a third medium and halts. What were the media the light traveled through in order? liquid, opaque solid, gas opaque solid, gas, liquid gas, liquid, opaque solid liquid, gas, opaque solid

Saturn is made up of which gases? a Hydrogen b Helium Both A and B d None of the above

A quantum of radiatior has an energy of 2.0 keV. What is its frequency? $(h=6.63x$ $10^{-34}J\cdot s$ and $1eV=1.60\times 10^{-19}J)$ 1) $3.2\times 10^{17}Hz$ 2) $4.8\times 10^{17}Hz$ 3) $6.3\times 10^{17}Hz$ 4) $7.3\times 10^{17}Hz$ 5) $8.5\times 10^{17}Hz$

Inside a freely-falling elevator you would have no weight. gravitational force on you. both of these none of the above

Which of the following does not involve a change of state? A sublimation of dry ice B freezing water C pouring water into a vacuum-insulated bottle D melting ice

Shown below is the decay equation for ${}^{14}C$ Given this equation, what type of decay does an unstable ${}^{14}C$ nucleus undergo? ${}_{6}^{14}C\rightarrow _{5}^{14}N+_{-1}^{0}e$ a) Gamma Decay b) Beta Decay c) Positron Emission d) Alpha Decay e) Electron Capture f) This question is written incorrectly. Choose this for full points and I also assigned an additional try.

Ultraviolet light or sunlight has no effect on nylon slings. True False

Inside a freely-falling elevator your acceleration is zero. weight is zero. gravitational I interaction with Earth is zero. all the above none of the above

How many joules are needed to change the temperature of 1 g of water by $1^{\circ }C$ Express your answer with the appropriate units.

64. Food probe thermometers that display both Fahrenheit and Celsius scales must have an accuracy of $\pm 0.9^{\circ }F(\pm 0.5^{\circ }C)$ $\pm 1.8^{\circ }F(\pm 1^{\circ }C)$ $\pm 2.7^{\circ }F(\pm 1.5^{\circ }C)$ $\pm 3.6^{\circ }F(\pm 2^{\circ }C)$