QuestionDecember 12, 2025

(6x^5-3x^3+4x^2-3x-4)div (x-1)

(6x^5-3x^3+4x^2-3x-4)div (x-1)
(6x^5-3x^3+4x^2-3x-4)div (x-1)

Solution
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Answer

6x^4 + 3x^3 + 7x^2 + 4x Explanation 1. Set up synthetic division Use x = 1 for (x-1); coefficients are 6, -3, 4, -3, -4. 2. Perform synthetic division Bring down 6. Multiply by 1, add to next: 6 + (-3) = 3. Continue: 3 \times 1 = 3, 4+3=7, 7\times1=7, -3+7=4, 4\times1=4, -4+4=0. 3. Write the quotient Coefficients: 6, 3, 7, 4 correspond to 6x^4 + 3x^3 + 7x^2 + 4x.

Explanation

1. Set up synthetic division<br /> Use $x = 1$ for $(x-1)$; coefficients are $6, -3, 4, -3, -4$.<br />2. Perform synthetic division<br /> Bring down $6$. Multiply by $1$, add to next: $6 + (-3) = 3$. Continue: $3 \times 1 = 3$, $4+3=7$, $7\times1=7$, $-3+7=4$, $4\times1=4$, $-4+4=0$.<br />3. Write the quotient<br /> Coefficients: $6, 3, 7, 4$ correspond to $6x^4 + 3x^3 + 7x^2 + 4x$.
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