QuestionJuly 15, 2025

Perform the indicated operation. (8a)/(b)-(3b)/(4) (8a)/(b)-(3b)/(4)= square (Simplify your answer.)

Perform the indicated operation. (8a)/(b)-(3b)/(4) (8a)/(b)-(3b)/(4)= square (Simplify your answer.)
Perform the indicated operation.
(8a)/(b)-(3b)/(4)
(8a)/(b)-(3b)/(4)= square  (Simplify your answer.)

Solution
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Answer

\frac{32a - 3b^2}{4b} Explanation 1. Find a common denominator The denominators are b and 4. The common denominator is 4b. 2. Rewrite each fraction with the common denominator \frac{8a}{b} = \frac{8a \cdot 4}{b \cdot 4} = \frac{32a}{4b} and \frac{3b}{4} = \frac{3b \cdot b}{4 \cdot b} = \frac{3b^2}{4b}. 3. Subtract the fractions \frac{32a}{4b} - \frac{3b^2}{4b} = \frac{32a - 3b^2}{4b}.

Explanation

1. Find a common denominator<br /> The denominators are $b$ and $4$. The common denominator is $4b$.<br /><br />2. Rewrite each fraction with the common denominator<br /> $\frac{8a}{b} = \frac{8a \cdot 4}{b \cdot 4} = \frac{32a}{4b}$ and $\frac{3b}{4} = \frac{3b \cdot b}{4 \cdot b} = \frac{3b^2}{4b}$.<br /><br />3. Subtract the fractions<br /> $\frac{32a}{4b} - \frac{3b^2}{4b} = \frac{32a - 3b^2}{4b}$.
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