QuestionDecember 20, 2025

If you place a-0.238C charge at a point where the electric field is 134N/C to the right, what electric force will it feel? () N Include a+or - sign to indicate the direction of the force.

If you place a-0.238C charge at a point where the electric field is 134N/C to the right, what electric force will it feel? () N Include a+or - sign to indicate the direction of the force.
If you place a-0.238C charge at a point
where the electric field is 134N/C to the
right, what electric force will it feel?
() N
Include a+or - sign to indicate the direction of the force.

Solution
4.5(301 votes)

Answer

F = -31.9\ \text{N} Explanation 1. Write the electric force formula The electric force on a charge in an electric field is given by **F = qE**. 2. Substitute known values q = -0.238\ \text{C} and E = 134\ \text{N/C}. So, F = (-0.238)(134). 3. Compute the result F = -31.892\ \text{N}. The negative sign means the force is **opposite** the direction of the electric field (to the left).

Explanation

1. Write the electric force formula<br /> The electric force on a charge in an electric field is given by **$F = qE$**.<br /><br />2. Substitute known values<br /> $q = -0.238\ \text{C}$ and $E = 134\ \text{N/C}$.<br /><br /> So, $F = (-0.238)(134)$.<br /><br />3. Compute the result<br /> $F = -31.892\ \text{N}$.<br /><br /> The negative sign means the force is **opposite** the direction of the electric field (to the left).
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