QuestionAugust 27, 2025

8 The result of dividing 2x^3+6x^2+7x+2byx+1 is (1) 2x^2+4x+3-(1)/(x+1) (3) 2x^2+8x-15+(17)/(x+1) (2) 2x^2+4x+3+(5)/(x+1) (4) 2x^2+8x+15-(13)/(x+1)

8 The result of dividing 2x^3+6x^2+7x+2byx+1 is (1) 2x^2+4x+3-(1)/(x+1) (3) 2x^2+8x-15+(17)/(x+1) (2) 2x^2+4x+3+(5)/(x+1) (4) 2x^2+8x+15-(13)/(x+1)
8 The result of dividing 2x^3+6x^2+7x+2byx+1 is
(1) 2x^2+4x+3-(1)/(x+1)
(3) 2x^2+8x-15+(17)/(x+1)
(2) 2x^2+4x+3+(5)/(x+1)
(4) 2x^2+8x+15-(13)/(x+1)

Solution
4.4(267 votes)

Answer

2x^2 + 4x + 3 - \frac{1}{x+1} Explanation 1. Perform Polynomial Division Divide 2x^3 + 6x^2 + 7x + 2 by x + 1 using synthetic division or long division. 1. Divide the leading term: \frac{2x^3}{x} = 2x^2. 2. Multiply and subtract: (2x^2)(x+1) = 2x^3 + 2x^2. Subtract from original to get 4x^2 + 7x + 2. 3. Repeat for 4x^2: \frac{4x^2}{x} = 4x. 4. Multiply and subtract: (4x)(x+1) = 4x^2 + 4x. Subtract to get 3x + 2. 5. Repeat for 3x: \frac{3x}{x} = 3. 6. Multiply and subtract: (3)(x+1) = 3x + 3. Subtract to get remainder -1. 2. Express the Result The quotient is 2x^2 + 4x + 3 with a remainder of -1. Thus, the expression becomes 2x^2 + 4x + 3 - \frac{1}{x+1}.

Explanation

1. Perform Polynomial Division<br /> Divide $2x^3 + 6x^2 + 7x + 2$ by $x + 1$ using synthetic division or long division.<br /><br />1. Divide the leading term: $\frac{2x^3}{x} = 2x^2$.<br />2. Multiply and subtract: $(2x^2)(x+1) = 2x^3 + 2x^2$. Subtract from original to get $4x^2 + 7x + 2$.<br />3. Repeat for $4x^2$: $\frac{4x^2}{x} = 4x$.<br />4. Multiply and subtract: $(4x)(x+1) = 4x^2 + 4x$. Subtract to get $3x + 2$.<br />5. Repeat for $3x$: $\frac{3x}{x} = 3$.<br />6. Multiply and subtract: $(3)(x+1) = 3x + 3$. Subtract to get remainder $-1$.<br /><br />2. Express the Result<br /> The quotient is $2x^2 + 4x + 3$ with a remainder of $-1$. Thus, the expression becomes $2x^2 + 4x + 3 - \frac{1}{x+1}$.
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