QuestionAugust 16, 2025

P_(2)O_(3)+3H_(2)Oarrow 2H_(3)PO_(3) How many grams of diphosphorus trioxide, P_(2)O_(3) . are required to react completely with 4.0 moles H_(2)O ? molar mass P_(2)O_(3):109.94g/mol [?]gP_(2)O_(3)

P_(2)O_(3)+3H_(2)Oarrow 2H_(3)PO_(3) How many grams of diphosphorus trioxide, P_(2)O_(3) . are required to react completely with 4.0 moles H_(2)O ? molar mass P_(2)O_(3):109.94g/mol [?]gP_(2)O_(3)
P_(2)O_(3)+3H_(2)Oarrow 2H_(3)PO_(3)
How many grams of diphosphorus
trioxide, P_(2)O_(3) . are required to react
completely with 4.0 moles H_(2)O ?
molar mass P_(2)O_(3):109.94g/mol
[?]gP_(2)O_(3)

Solution
4.1(159 votes)

Answer

146.59 g P_{2}O_{3} Explanation 1. Determine mole ratio from balanced equation From the equation, 1 mole of P_2O_3 reacts with 3 moles of H_2O. 2. Calculate moles of P_2O_3 needed For 4.0 moles of H_2O, use the ratio: \frac{1 \text{ mole } P_2O_3}{3 \text{ moles } H_2O}. Thus, moles of P_2O_3 = \frac{4.0}{3}. 3. Convert moles of P_2O_3 to grams Use the formula: **mass = moles \times molar mass**. Mass of P_2O_3 = \frac{4.0}{3} \times 109.94 g/mol.

Explanation

1. Determine mole ratio from balanced equation<br /> From the equation, 1 mole of $P_2O_3$ reacts with 3 moles of $H_2O$.<br />2. Calculate moles of $P_2O_3$ needed<br /> For 4.0 moles of $H_2O$, use the ratio: $\frac{1 \text{ mole } P_2O_3}{3 \text{ moles } H_2O}$. Thus, moles of $P_2O_3 = \frac{4.0}{3}$.<br />3. Convert moles of $P_2O_3$ to grams<br /> Use the formula: **mass = moles $\times$ molar mass**. Mass of $P_2O_3 = \frac{4.0}{3} \times 109.94$ g/mol.
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