QuestionJune 18, 2025

8. Solve the following trig equation 10sin(x-2)=-7 square

8. Solve the following trig equation 10sin(x-2)=-7 square
8. Solve the following trig equation
10sin(x-2)=-7
square

Solution
3.8(336 votes)

Answer

x \approx 1.225 + 2k\pi or x \approx 3.916 + 2k\pi, k \in \mathbb{Z} Explanation 1. Isolate the sine function Divide both sides by 10: sin(x-2) = -0.7 2. Find the angle Use inverse sine: x-2 = sin^{-1}(-0.7) 3. Calculate principal value sin^{-1}(-0.7) \approx -0.775 4. Solve for x Add 2 to both sides: x \approx 2 - 0.775 5. Consider periodic solutions Since sine is periodic with period 2\pi, general solution: x = 2 - 0.775 + 2k\pi or x = \pi - (2 - 0.775) + 2k\pi, where k is an integer.

Explanation

1. Isolate the sine function<br /> Divide both sides by 10: $sin(x-2) = -0.7$<br />2. Find the angle<br /> Use inverse sine: $x-2 = sin^{-1}(-0.7)$<br />3. Calculate principal value<br /> $sin^{-1}(-0.7) \approx -0.775$<br />4. Solve for x<br /> Add 2 to both sides: $x \approx 2 - 0.775$<br />5. Consider periodic solutions<br /> Since sine is periodic with period $2\pi$, general solution: $x = 2 - 0.775 + 2k\pi$ or $x = \pi - (2 - 0.775) + 2k\pi$, where $k$ is an integer.
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