QUESTION 16 What element results when 2 protons are added to a vanadium atom? ManganeseMn

What is the purpose of the binder in paint? Select one: a. To act as a preliminary coat without which oil paint cannot adhere to the canvas. b. An ingredient to help differentiate watercolors from oil paints. C. To ensure that the paint will adhere to the surface and not fall off as it dries. d. To help the paint to dissolve, mix and spread, as the artist works with it.

Copper is plated on zinc by immersing a piece of zinc into a solution containing copper(II) ions. In the plating reaction, zinc loses two electrons and is reduced. loses two electrons and is oxidized. gains two electrons and is oxidized. gains two electrons and is reduced.

$[H_{3}O^{+}]=6.8\times 10^{-2}M$ $[OH^{-}]=\square M$ This solution is (Choose one)

Question 7 (2 points) Show your work. For the balanced chemical reaction below, how many moles of $CO_{2}$ are produced when 729.0 moles of $O_{2}$ react? $2C_{6}H_{6}(e)+15O_{2}(g)\rightarrow 12CO_{2}(g)+6H_{2}O(e)$ Round your answer to one decimal place. Your Answer: $\square $ $\square $ Answer units

During what stage will flames extend out of the compartment openings because there is insufficient oxygen for complete combustion in the compartment? (108) Select one: a. Decay b. Growth c. Incipient d. Fully developed

Determine the number of moles in $5.50\times 10^{23}$ formula units of $MgBr_{2}$ $\square $

The bond between two hydrogen atoms (a covalent bond) is based on the force of 'attraction between __ two ions two nuclei two atoms protons and electrons in the same atom

$Zn(OH)_{2}$ has a $K_{sp}$ of $4.5\times 10^{-17}$ If you have a solution of $Zn(OH)_{2}$ that has a hydroxide ion concentration equal to $4.6\times 10^{-6}M$ what is the solution? unsaturated supersaturated No answer text provided. saturated

Strong bases dissociate only slightly in water. True False

Which value gives the number of particles in 1 mol of a-subsiance? $6.02\times 10^{21}$ $6.02\times 10^{22}$ $6.02\times 10^{23}$ $6.02\times 10^{24}$