QuestionJune 3, 2025

Writing Net Ionic Equations Exercise:Determine the following for the chemical reaction below: HC_(2)H_(3)O_(2(aq))+Ca(OH)_(2(aq))arrow Ca(C_(2)H_(3)O_(2))_(2(aq))+H_(2)O_((l)) a. total ionic equation b. spectator ions (if any) c. net ionic equation

Writing Net Ionic Equations Exercise:Determine the following for the chemical reaction below: HC_(2)H_(3)O_(2(aq))+Ca(OH)_(2(aq))arrow Ca(C_(2)H_(3)O_(2))_(2(aq))+H_(2)O_((l)) a. total ionic equation b. spectator ions (if any) c. net ionic equation
Writing Net Ionic Equations Exercise:Determine the following for the chemical reaction below: HC_(2)H_(3)O_(2(aq))+Ca(OH)_(2(aq))arrow Ca(C_(2)H_(3)O_(2))_(2(aq))+H_(2)O_((l)) a. total ionic equation b. spectator ions (if any) c. net ionic equation

Solution
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Answer

a. Total ionic equation: HC_{2}H_{3}O_{2(aq)} + Ca^{2+}_{(aq)} + 2OH^{-}_{(aq)} \rightarrow Ca^{2+}_{(aq)} + 2C_{2}H_{3}O_{2}^{-}_{(aq)} + 2H_{2}O_{(l)} ### b. Spectator ions: Ca^{2+} ### c. Net ionic equation: HC_{2}H_{3}O_{2(aq)} + 2OH^{-}_{(aq)} \rightarrow 2C_{2}H_{3}O_{2}^{-}_{(aq)} + 2H_{2}O_{(l)} Explanation 1. Write the balanced molecular equation The given reaction is already balanced: HC_{2}H_{3}O_{2(aq)} + Ca(OH)_{2(aq)} \rightarrow Ca(C_{2}H_{3}O_{2})_{2(aq)} + 2H_{2}O_{(l)}. 2. Write the total ionic equation Break all strong electrolytes into ions: - HC_{2}H_{3}O_{2} is a weak acid, so it remains as molecules. - Ca(OH)_{2} dissociates into Ca^{2+}_{(aq)} + 2OH^{-}_{(aq)}. - Ca(C_{2}H_{3}O_{2})_{2} dissociates into Ca^{2+}_{(aq)} + 2C_{2}H_{3}O_{2}^{-}_{(aq)}. - Water (H_{2}O) remains as molecules. Total ionic equation: HC_{2}H_{3}O_{2(aq)} + Ca^{2+}_{(aq)} + 2OH^{-}_{(aq)} \rightarrow Ca^{2+}_{(aq)} + 2C_{2}H_{3}O_{2}^{-}_{(aq)} + 2H_{2}O_{(l)} 3. Identify spectator ions Spectator ions do not change during the reaction. Here, Ca^{2+} appears on both sides of the equation. 4. Write the net ionic equation Remove spectator ions from the total ionic equation: HC_{2}H_{3}O_{2(aq)} + 2OH^{-}_{(aq)} \rightarrow 2C_{2}H_{3}O_{2}^{-}_{(aq)} + 2H_{2}O_{(l)}

Explanation

1. Write the balanced molecular equation<br /> The given reaction is already balanced: $HC_{2}H_{3}O_{2(aq)} + Ca(OH)_{2(aq)} \rightarrow Ca(C_{2}H_{3}O_{2})_{2(aq)} + 2H_{2}O_{(l)}$.<br /><br />2. Write the total ionic equation<br /> Break all strong electrolytes into ions:<br />- $HC_{2}H_{3}O_{2}$ is a weak acid, so it remains as molecules.<br />- $Ca(OH)_{2}$ dissociates into $Ca^{2+}_{(aq)} + 2OH^{-}_{(aq)}$.<br />- $Ca(C_{2}H_{3}O_{2})_{2}$ dissociates into $Ca^{2+}_{(aq)} + 2C_{2}H_{3}O_{2}^{-}_{(aq)}$.<br />- Water ($H_{2}O$) remains as molecules.<br /><br />Total ionic equation:<br />$HC_{2}H_{3}O_{2(aq)} + Ca^{2+}_{(aq)} + 2OH^{-}_{(aq)} \rightarrow Ca^{2+}_{(aq)} + 2C_{2}H_{3}O_{2}^{-}_{(aq)} + 2H_{2}O_{(l)}$<br /><br />3. Identify spectator ions<br /> Spectator ions do not change during the reaction. Here, $Ca^{2+}$ appears on both sides of the equation.<br /><br />4. Write the net ionic equation<br /> Remove spectator ions from the total ionic equation:<br />$HC_{2}H_{3}O_{2(aq)} + 2OH^{-}_{(aq)} \rightarrow 2C_{2}H_{3}O_{2}^{-}_{(aq)} + 2H_{2}O_{(l)}$
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