QuestionApril 30, 2025

Convert 3.98times 10^25 molecules of Be_(3)N_(2) to grams of Be_(3)N_(2)

Convert 3.98times 10^25 molecules of Be_(3)N_(2) to grams of Be_(3)N_(2)
Convert 3.98times 10^25 molecules of Be_(3)N_(2) to grams of Be_(3)N_(2)

Solution
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Answer

3640.93 grams of Be_{3}N_{2} Explanation 1. Calculate moles of Be_{3}N_{2} Use **n = \frac{N}{N_A}**, where N = 3.98 \times 10^{25} and N_A = 6.022 \times 10^{23} (Avogadro's number). n = \frac{3.98 \times 10^{25}}{6.022 \times 10^{23}} \approx 66.09 moles. 2. Calculate molar mass of Be_{3}N_{2} Molar mass = 3 \times 9.012 + 2 \times 14.007 = 55.08 g/mol. 3. Convert moles to grams Use **m = n \times M**, where n = 66.09 moles and M = 55.08 g/mol. m = 66.09 \times 55.08 \approx 3640.93 grams.

Explanation

1. Calculate moles of $Be_{3}N_{2}$<br /> Use **$n = \frac{N}{N_A}$**, where $N = 3.98 \times 10^{25}$ and $N_A = 6.022 \times 10^{23}$ (Avogadro's number). <br /> $n = \frac{3.98 \times 10^{25}}{6.022 \times 10^{23}} \approx 66.09$ moles.<br /><br />2. Calculate molar mass of $Be_{3}N_{2}$<br /> Molar mass = $3 \times 9.012 + 2 \times 14.007 = 55.08$ g/mol.<br /><br />3. Convert moles to grams<br /> Use **$m = n \times M$**, where $n = 66.09$ moles and $M = 55.08$ g/mol.<br /> $m = 66.09 \times 55.08 \approx 3640.93$ grams.
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