QuestionMay 5, 2025

Block 5.5 Assignment:Heat calculations 3350 J of heat is required to raise the temperature of a sample of AlF_(3) from 25^circ C to 80^circ C What is the mass of the sample? m=square g (Format: XXXX)

Block 5.5 Assignment:Heat calculations 3350 J of heat is required to raise the temperature of a sample of AlF_(3) from 25^circ C to 80^circ C What is the mass of the sample? m=square g (Format: XXXX)
Block 5.5 Assignment:Heat calculations 3350 J of heat is required to raise the temperature of a sample of AlF_(3) from 25^circ C to 80^circ C What is the mass of the sample? m=square g (Format: XXXX)

Solution
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Answer

0684 Explanation 1. Use the heat transfer formula The formula is q = mc\Delta T, where q is heat, m is mass, c is specific heat capacity, and \Delta T is the temperature change. Rearrange for m: m = \frac{q}{c\Delta T}. 2. Calculate \Delta T \Delta T = 80^{\circ}C - 25^{\circ}C = 55^{\circ}C. 3. Substitute known values For AlF_3, c = 0.89 \, \text{J/g°C} (specific heat capacity). Substituting: m = \frac{3350}{0.89 \cdot 55}. 4. Perform the calculation m = \frac{3350}{48.95} \approx 68.41 \, \text{g}.

Explanation

1. Use the heat transfer formula<br /> The formula is $q = mc\Delta T$, where $q$ is heat, $m$ is mass, $c$ is specific heat capacity, and $\Delta T$ is the temperature change. Rearrange for $m$: $m = \frac{q}{c\Delta T}$.<br /><br />2. Calculate $\Delta T$<br /> $\Delta T = 80^{\circ}C - 25^{\circ}C = 55^{\circ}C$.<br /><br />3. Substitute known values<br /> For $AlF_3$, $c = 0.89 \, \text{J/g°C}$ (specific heat capacity). Substituting: <br />$m = \frac{3350}{0.89 \cdot 55}$.<br /><br />4. Perform the calculation<br /> $m = \frac{3350}{48.95} \approx 68.41 \, \text{g}$.
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