QuestionJuly 1, 2025

What is the net ionic equation for the reaction of HCl with NaOH? HCl+NaOHarrow H_(2)O+NaCl H^++OH^-arrow H_(2)O 2H^++2Cl^-+Na_(2)^++2OH-arrow H_(2)O+Na_(2)^++2Cl^- H^++Cl^-+Na^++OH-arrow H_(2)O+Na^++Cl^-

What is the net ionic equation for the reaction of HCl with NaOH? HCl+NaOHarrow H_(2)O+NaCl H^++OH^-arrow H_(2)O 2H^++2Cl^-+Na_(2)^++2OH-arrow H_(2)O+Na_(2)^++2Cl^- H^++Cl^-+Na^++OH-arrow H_(2)O+Na^++Cl^-
What is the net ionic equation for the reaction of HCl with NaOH?
HCl+NaOHarrow H_(2)O+NaCl
H^++OH^-arrow H_(2)O
2H^++2Cl^-+Na_(2)^++2OH-arrow H_(2)O+Na_(2)^++2Cl^-
H^++Cl^-+Na^++OH-arrow H_(2)O+Na^++Cl^-

Solution
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Answer

\mathrm{H}^{+} + \mathrm{OH}^{-} \rightarrow \mathrm{H}_{2}\mathrm{O} Explanation 1. Identify the complete ionic equation Break down all aqueous compounds into ions: \mathrm{HCl} \rightarrow \mathrm{H}^{+} + \mathrm{Cl}^{-} , \mathrm{NaOH} \rightarrow \mathrm{Na}^{+} + \mathrm{OH}^{-} . The products are \mathrm{H}_{2}\mathrm{O} (liquid, not ionized) and \mathrm{NaCl} \rightarrow \mathrm{Na}^{+} + \mathrm{Cl}^{-} . 2. Cancel spectator ions Spectator ions (\mathrm{Na}^{+} and \mathrm{Cl}^{-}) appear on both sides of the equation. Remove them to find the net ionic equation. 3. Write the net ionic equation After removing spectator ions, the remaining ions form the net ionic equation: \mathrm{H}^{+} + \mathrm{OH}^{-} \rightarrow \mathrm{H}_{2}\mathrm{O} .

Explanation

1. Identify the complete ionic equation<br /> Break down all aqueous compounds into ions: $ \mathrm{HCl} \rightarrow \mathrm{H}^{+} + \mathrm{Cl}^{-} $, $ \mathrm{NaOH} \rightarrow \mathrm{Na}^{+} + \mathrm{OH}^{-} $. The products are $ \mathrm{H}_{2}\mathrm{O} $ (liquid, not ionized) and $ \mathrm{NaCl} \rightarrow \mathrm{Na}^{+} + \mathrm{Cl}^{-} $.<br /><br />2. Cancel spectator ions<br /> Spectator ions ($\mathrm{Na}^{+}$ and $\mathrm{Cl}^{-}$) appear on both sides of the equation. Remove them to find the net ionic equation.<br /><br />3. Write the net ionic equation<br /> After removing spectator ions, the remaining ions form the net ionic equation: $ \mathrm{H}^{+} + \mathrm{OH}^{-} \rightarrow \mathrm{H}_{2}\mathrm{O} $.
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