QuestionJune 27, 2025

?arrow _(50)^121Sn+_(2)^4He In the equation above determine the parent isotope by name and mass number. square square

?arrow _(50)^121Sn+_(2)^4He In the equation above determine the parent isotope by name and mass number. square square
?arrow _(50)^121Sn+_(2)^4He In the equation above determine the parent isotope by name and mass number. square square

Solution
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Answer

Tellurium-125 Explanation 1. Identify the Reaction Type This is a nuclear reaction where an alpha particle _{2}^{4}He is emitted. 2. Apply Conservation of Mass Number The mass number before and after the reaction must be equal. Let A be the mass number of the parent isotope. Then, A = 121 + 4 = 125. 3. Apply Conservation of Atomic Number The atomic number before and after the reaction must be equal. Let Z be the atomic number of the parent isotope. Then, Z = 50 + 2 = 52. 4. Determine the Element The element with atomic number 52 is Tellurium (Te).

Explanation

1. Identify the Reaction Type<br /> This is a nuclear reaction where an alpha particle $_{2}^{4}He$ is emitted.<br />2. Apply Conservation of Mass Number<br /> The mass number before and after the reaction must be equal. Let $A$ be the mass number of the parent isotope. Then, $A = 121 + 4 = 125$.<br />3. Apply Conservation of Atomic Number<br /> The atomic number before and after the reaction must be equal. Let $Z$ be the atomic number of the parent isotope. Then, $Z = 50 + 2 = 52$.<br />4. Determine the Element<br /> The element with atomic number 52 is Tellurium (Te).
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