QuestionJuly 21, 2025

A point is subjected to 5 ksi biaxial tension. The diameter of the corresponding Mohr's circle is most nearly: O 5 ksi 7.07 ksi 10 ksi

A point is subjected to 5 ksi biaxial tension. The diameter of the corresponding Mohr's circle is most nearly: O 5 ksi 7.07 ksi 10 ksi
A point is subjected to 5 ksi biaxial tension. The diameter of the corresponding
Mohr's circle is most nearly:
O
5 ksi
7.07 ksi
10 ksi

Solution
4.5(252 votes)

Answer

5 ksi Explanation 1. Identify the Principal Stresses In biaxial tension, the principal stresses are \sigma_1 = 5 \text{ ksi} and \sigma_2 = 0 \text{ ksi}. 2. Calculate Mohr's Circle Diameter The diameter of Mohr's circle is given by the difference between the principal stresses: **Diameter = \sigma_1 - \sigma_2**. 3. Compute the Diameter Substitute the values: Diameter = 5 \text{ ksi} - 0 \text{ ksi} = 5 \text{ ksi}.

Explanation

1. Identify the Principal Stresses<br /> In biaxial tension, the principal stresses are $\sigma_1 = 5 \text{ ksi}$ and $\sigma_2 = 0 \text{ ksi}$.<br /><br />2. Calculate Mohr's Circle Diameter<br /> The diameter of Mohr's circle is given by the difference between the principal stresses: **Diameter = $\sigma_1 - \sigma_2$**.<br /><br />3. Compute the Diameter<br /> Substitute the values: Diameter = $5 \text{ ksi} - 0 \text{ ksi} = 5 \text{ ksi}$.
Click to rate:

Similar Questions