QuestionJuly 29, 2025

A car moving at 35.2m/s accelerates uniformly to 45.0m/s over 2.25 s. What is the acceleration of the car? a=[?]m/s^2

A car moving at 35.2m/s accelerates uniformly to 45.0m/s over 2.25 s. What is the acceleration of the car? a=[?]m/s^2
A car moving at 35.2m/s accelerates uniformly to 45.0m/s over 2.25 s. What is the acceleration of the car? a=[?]m/s^2

Solution
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Answer

4.36 \, m/s^2 Explanation 1. Identify Initial and Final Velocities Initial velocity u = 35.2 \, m/s, final velocity v = 45.0 \, m/s. 2. Identify Time Interval Time t = 2.25 \, s. 3. Use the Acceleration Formula Use **a = \frac{v - u}{t}** to find acceleration. 4. Calculate Acceleration a = \frac{45.0 \, m/s - 35.2 \, m/s}{2.25 \, s} = \frac{9.8 \, m/s}{2.25 \, s} = 4.36 \, m/s^2.

Explanation

1. Identify Initial and Final Velocities<br /> Initial velocity $u = 35.2 \, m/s$, final velocity $v = 45.0 \, m/s$.<br />2. Identify Time Interval<br /> Time $t = 2.25 \, s$.<br />3. Use the Acceleration Formula<br /> Use **$a = \frac{v - u}{t}$** to find acceleration.<br />4. Calculate Acceleration<br /> $a = \frac{45.0 \, m/s - 35.2 \, m/s}{2.25 \, s} = \frac{9.8 \, m/s}{2.25 \, s} = 4.36 \, m/s^2$.
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