QuestionDecember 26, 2025

A circle centered at A(3,4) passes through the point B(6,8) What is the equation of the circle? Type your answers in the boxes. (x-square )^2+(y-square )^2=square

A circle centered at A(3,4) passes through the point B(6,8) What is the equation of the circle? Type your answers in the boxes. (x-square )^2+(y-square )^2=square
A circle centered at A(3,4) passes through the point B(6,8) What is the equation of the circle?
Type your answers in the boxes.
(x-square )^2+(y-square )^2=square

Solution
4.5(240 votes)

Answer

(x-3)^2 + (y-4)^2 = 25 Explanation 1. Find the radius Use distance formula: r = \sqrt{(6-3)^2 + (8-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 2. Write the equation of the circle Standard form: (x-h)^2 + (y-k)^2 = r^2 with center (h, k) = (3, 4) and r = 5

Explanation

1. Find the radius<br /> Use distance formula: $r = \sqrt{(6-3)^2 + (8-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5$<br />2. Write the equation of the circle<br /> Standard form: $(x-h)^2 + (y-k)^2 = r^2$ with center $(h, k) = (3, 4)$ and $r = 5$
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