QuestionJuly 15, 2025

Find the solution to the following system of equations. Enter your answer as an ordered pair in the form (x,y) if there is one unique solution. Enter All if there are infinitely many solutions and enter None if there are no solutions. 5x-6y=31 -10x-12y=-38

Find the solution to the following system of equations. Enter your answer as an ordered pair in the form (x,y) if there is one unique solution. Enter All if there are infinitely many solutions and enter None if there are no solutions. 5x-6y=31 -10x-12y=-38
Find the solution to the following system of equations. Enter your answer as an ordered
pair in the form (x,y) if there is one unique solution. Enter All if there are infinitely many
solutions and enter None if there are no solutions.
5x-6y=31
-10x-12y=-38

Solution
4.1(374 votes)

Answer

None Explanation 1. Multiply the first equation Multiply the first equation by 2 to align coefficients of x: 2(5x - 6y) = 2(31), resulting in 10x - 12y = 62. 2. Compare equations Compare 10x - 12y = 62 with -10x - 12y = -38. The left sides are not identical, indicating no solutions. 3. Check for contradictions Adding the two equations: (10x - 12y) + (-10x - 12y) = 62 - 38, simplifies to 0 \neq 24, confirming a contradiction.

Explanation

1. Multiply the first equation<br /> Multiply the first equation by 2 to align coefficients of $x$: $2(5x - 6y) = 2(31)$, resulting in $10x - 12y = 62$.<br />2. Compare equations<br /> Compare $10x - 12y = 62$ with $-10x - 12y = -38$. The left sides are not identical, indicating no solutions.<br />3. Check for contradictions<br /> Adding the two equations: $(10x - 12y) + (-10x - 12y) = 62 - 38$, simplifies to $0 \neq 24$, confirming a contradiction.
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