QuestionMay 1, 2025

A student is using these conversion factors to convert from 2.5 grams of the given reactant to the mass of product. Identify any conversion factors that would NOT work. Tap to select or deselect an answer. Select all that would NOT work. 2Al+3CuCl_(2)arrow 2AlCl_(3)+3Cu 2.5gAltimes (1molAl)/(27.0gAl)times (2molCu)/(3molAl)times (63.5gCu)/(1molCu) N_(2)+3H_(2)arrow 2NH_(3) 2.5gH_(2)times (1molH_(2))/(2.0gH_(2))times (2molNH_(3))/(3molH_(2))times (17.0gNH_(3))/(1molNH_(3)) 2Cu+Sarrow Cu_(2)S 2.5gCutimes (1gCu_(2)S)/(2gCu)times (63.5gCu)/(1molCu)times (1molCu_(2)S)/(159.2gCu_(2)S)

A student is using these conversion factors to convert from 2.5 grams of the given reactant to the mass of product. Identify any conversion factors that would NOT work. Tap to select or deselect an answer. Select all that would NOT work. 2Al+3CuCl_(2)arrow 2AlCl_(3)+3Cu 2.5gAltimes (1molAl)/(27.0gAl)times (2molCu)/(3molAl)times (63.5gCu)/(1molCu) N_(2)+3H_(2)arrow 2NH_(3) 2.5gH_(2)times (1molH_(2))/(2.0gH_(2))times (2molNH_(3))/(3molH_(2))times (17.0gNH_(3))/(1molNH_(3)) 2Cu+Sarrow Cu_(2)S 2.5gCutimes (1gCu_(2)S)/(2gCu)times (63.5gCu)/(1molCu)times (1molCu_(2)S)/(159.2gCu_(2)S)
A student is using these conversion factors to convert from 2.5 grams of the given
reactant to the mass of product. Identify any conversion factors that would NOT
work.
Tap to select or deselect an answer. Select all that would NOT work.
2Al+3CuCl_(2)arrow 2AlCl_(3)+3Cu
2.5gAltimes (1molAl)/(27.0gAl)times (2molCu)/(3molAl)times (63.5gCu)/(1molCu)
N_(2)+3H_(2)arrow 2NH_(3)
2.5gH_(2)times (1molH_(2))/(2.0gH_(2))times (2molNH_(3))/(3molH_(2))times (17.0gNH_(3))/(1molNH_(3))
2Cu+Sarrow Cu_(2)S
2.5gCutimes (1gCu_(2)S)/(2gCu)times (63.5gCu)/(1molCu)times (1molCu_(2)S)/(159.2gCu_(2)S)

Solution
4.7(287 votes)

Answer

The conversion factor \frac{1gCu_2S}{2gCu} does NOT work. Explanation 1. Analyze the first reaction conversion factors Reaction: 2Al + 3CuCl_2 \rightarrow 2AlCl_3 + 3Cu. The given conversion factors are: 2.5gAl \times \frac{1molAl}{27.0gAl} \times \frac{2molCu}{3molAl} \times \frac{63.5gCu}{1molCu}. - \frac{1molAl}{27.0gAl} is correct for converting grams of Al to moles. - \frac{2molCu}{3molAl} is correct based on the stoichiometric ratio. - \frac{63.5gCu}{1molCu} is correct for converting moles of Cu to grams. **All conversion factors work here.** --- 2. Analyze the second reaction conversion factors Reaction: N_2 + 3H_2 \rightarrow 2NH_3. The given conversion factors are: 2.5gH_2 \times \frac{1molH_2}{2.0gH_2} \times \frac{2molNH_3}{3molH_2} \times \frac{17.0gNH_3}{1molNH_3}. - \frac{1molH_2}{2.0gH_2} is correct for converting grams of H_2 to moles. - \frac{2molNH_3}{3molH_2} is correct based on the stoichiometric ratio. - \frac{17.0gNH_3}{1molNH_3} is correct for converting moles of NH_3 to grams. **All conversion factors work here.** --- 3. Analyze the third reaction conversion factors Reaction: 2Cu + S \rightarrow Cu_2S. The given conversion factors are: 2.5gCu \times \frac{1gCu_2S}{2gCu} \times \frac{63.5gCu}{1molCu} \times \frac{1molCu_2S}{159.2gCu_2S}. - \frac{1gCu_2S}{2gCu} **does not work** because it incorrectly relates mass of Cu_2S to mass of Cu (should use molar masses and stoichiometry). - \frac{63.5gCu}{1molCu} is correct for converting moles of Cu to grams. - \frac{1molCu_2S}{159.2gCu_2S} is correct for converting grams of Cu_2S to moles. **The first factor (\frac{1gCu_2S}{2gCu}) does not work.** ---

Explanation

1. Analyze the first reaction conversion factors<br /> Reaction: $2Al + 3CuCl_2 \rightarrow 2AlCl_3 + 3Cu$. <br />The given conversion factors are:<br />$2.5gAl \times \frac{1molAl}{27.0gAl} \times \frac{2molCu}{3molAl} \times \frac{63.5gCu}{1molCu}$.<br /><br />- $\frac{1molAl}{27.0gAl}$ is correct for converting grams of Al to moles.<br />- $\frac{2molCu}{3molAl}$ is correct based on the stoichiometric ratio.<br />- $\frac{63.5gCu}{1molCu}$ is correct for converting moles of Cu to grams.<br /><br />**All conversion factors work here.**<br /><br />---<br /><br />2. Analyze the second reaction conversion factors<br /> Reaction: $N_2 + 3H_2 \rightarrow 2NH_3$. <br />The given conversion factors are:<br />$2.5gH_2 \times \frac{1molH_2}{2.0gH_2} \times \frac{2molNH_3}{3molH_2} \times \frac{17.0gNH_3}{1molNH_3}$.<br /><br />- $\frac{1molH_2}{2.0gH_2}$ is correct for converting grams of $H_2$ to moles.<br />- $\frac{2molNH_3}{3molH_2}$ is correct based on the stoichiometric ratio.<br />- $\frac{17.0gNH_3}{1molNH_3}$ is correct for converting moles of $NH_3$ to grams.<br /><br />**All conversion factors work here.**<br /><br />---<br /><br />3. Analyze the third reaction conversion factors<br /> Reaction: $2Cu + S \rightarrow Cu_2S$. <br />The given conversion factors are:<br />$2.5gCu \times \frac{1gCu_2S}{2gCu} \times \frac{63.5gCu}{1molCu} \times \frac{1molCu_2S}{159.2gCu_2S}$.<br /><br />- $\frac{1gCu_2S}{2gCu}$ **does not work** because it incorrectly relates mass of $Cu_2S$ to mass of $Cu$ (should use molar masses and stoichiometry).<br />- $\frac{63.5gCu}{1molCu}$ is correct for converting moles of Cu to grams.<br />- $\frac{1molCu_2S}{159.2gCu_2S}$ is correct for converting grams of $Cu_2S$ to moles.<br /><br />**The first factor ($\frac{1gCu_2S}{2gCu}$) does not work.**<br /><br />---
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