QuestionAugust 18, 2025

This is the chemical formula for chromium (III) carbonate: Cr_(2)(CO_(3))_(3) Calculate the mass percent of oxygen in chromium (III) carbonate. Round your answer to the nearest percentage. square %

This is the chemical formula for chromium (III) carbonate: Cr_(2)(CO_(3))_(3) Calculate the mass percent of oxygen in chromium (III) carbonate. Round your answer to the nearest percentage. square %
This is the chemical formula for chromium (III) carbonate: Cr_(2)(CO_(3))_(3) Calculate the mass percent of oxygen in chromium (III) carbonate. Round your answer to the nearest percentage. square %

Solution
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Answer

69% Explanation 1. Calculate Molar Mass of Cr_{2}(CO_{3})_{3} Chromium (Cr) has a molar mass of 52.00 g/mol, Carbon (C) is 12.01 g/mol, and Oxygen (O) is 16.00 g/mol. The formula Cr_{2}(CO_{3})_{3} consists of 2 Cr, 3 C, and 9 O atoms. Calculate the total molar mass: \[ \text{Molar mass} = 2(52.00) + 3(12.01) + 9(16.00) = 208.02 \, \text{g/mol} \] 2. Calculate Total Mass of Oxygen There are 9 oxygen atoms in the compound. Calculate their total mass: \[ \text{Mass of O} = 9 \times 16.00 = 144.00 \, \text{g/mol} \] 3. Calculate Mass Percent of Oxygen Use the formula for mass percent: **Mass Percent = \frac{\text{Mass of element}}{\text{Total molar mass}} \times 100** \[ \text{Mass Percent of O} = \frac{144.00}{208.02} \times 100 \approx 69\% \]

Explanation

1. Calculate Molar Mass of $Cr_{2}(CO_{3})_{3}$<br /> Chromium (Cr) has a molar mass of 52.00 g/mol, Carbon (C) is 12.01 g/mol, and Oxygen (O) is 16.00 g/mol. The formula $Cr_{2}(CO_{3})_{3}$ consists of 2 Cr, 3 C, and 9 O atoms. Calculate the total molar mass: <br />\[ <br />\text{Molar mass} = 2(52.00) + 3(12.01) + 9(16.00) = 208.02 \, \text{g/mol}<br />\]<br /><br />2. Calculate Total Mass of Oxygen<br /> There are 9 oxygen atoms in the compound. Calculate their total mass:<br />\[ <br />\text{Mass of O} = 9 \times 16.00 = 144.00 \, \text{g/mol}<br />\]<br /><br />3. Calculate Mass Percent of Oxygen<br /> Use the formula for mass percent: **Mass Percent = \frac{\text{Mass of element}}{\text{Total molar mass}} \times 100**<br />\[ <br />\text{Mass Percent of O} = \frac{144.00}{208.02} \times 100 \approx 69\%<br />\]
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