QuestionJuly 25, 2025

A closed vessel at 25^circ C and constant pressure contains the reversible reaction N_(2)O_(4)(g)leftharpoons 2NO_(2)(g) After sufficient time, the mixture reaches equilibrium. A reference standard thermodynamic quantities table is accessible using the button below or by clicking here. What is the value of Delta S_(rxn) for the system at this equilibrium state?

A closed vessel at 25^circ C and constant pressure contains the reversible reaction N_(2)O_(4)(g)leftharpoons 2NO_(2)(g) After sufficient time, the mixture reaches equilibrium. A reference standard thermodynamic quantities table is accessible using the button below or by clicking here. What is the value of Delta S_(rxn) for the system at this equilibrium state?
A closed vessel at 25^circ C and constant pressure contains the reversible reaction
N_(2)O_(4)(g)leftharpoons 2NO_(2)(g)
After sufficient time, the mixture reaches equilibrium.
A reference standard thermodynamic quantities table is accessible using the button below or by clicking here.
What is the value of Delta S_(rxn) for the system at this equilibrium state?

Solution
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Answer

\Delta S_{rxn} = 114.8 \, \text{J/mol K} (assuming standard values are used) Explanation 1. Identify the Reaction Entropy Change Formula The entropy change for a reaction is given by **\Delta S_{rxn} = \sum \Delta S_{products} - \sum \Delta S_{reactants}**. 2. Determine Standard Molar Entropies Use standard thermodynamic tables to find S^\circ values for N_2O_4(g) and NO_2(g). 3. Calculate \Delta S_{rxn} Apply the formula: \Delta S_{rxn} = [2 \times S^\circ(NO_2)] - [S^\circ(N_2O_4)].

Explanation

1. Identify the Reaction Entropy Change Formula<br /> The entropy change for a reaction is given by **$\Delta S_{rxn} = \sum \Delta S_{products} - \sum \Delta S_{reactants}$**.<br /><br />2. Determine Standard Molar Entropies<br /> Use standard thermodynamic tables to find $S^\circ$ values for $N_2O_4(g)$ and $NO_2(g)$.<br /><br />3. Calculate $\Delta S_{rxn}$<br /> Apply the formula: $\Delta S_{rxn} = [2 \times S^\circ(NO_2)] - [S^\circ(N_2O_4)]$.
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