QuestionMarch 21, 2026

Which action would speed up the reaction for the chemical reaction CH_(3)Br+OH^-arrow CH_(3)OH+Br^- increasing the CH3Br concentration reducing the OH- concentration cooling the reactant mixture reducing the pressure of the reactant mixture

Which action would speed up the reaction for the chemical reaction CH_(3)Br+OH^-arrow CH_(3)OH+Br^- increasing the CH3Br concentration reducing the OH- concentration cooling the reactant mixture reducing the pressure of the reactant mixture
Which action would speed up the reaction for the chemical reaction
CH_(3)Br+OH^-arrow CH_(3)OH+Br^-
increasing the CH3Br concentration
reducing the OH- concentration
cooling the reactant mixture
reducing the pressure of the reactant mixture

Solution
4.4(164 votes)

Answer

Increasing the CH_3Br concentration Explanation 1. Identify reaction type This is an SN2 reaction where rate depends on both CH_3Br and OH^-. 2. Apply rate law **Rate = k[CH₃Br][OH⁻]** — increasing either concentration increases rate; decreasing either slows it. 3. Evaluate options Increasing CH_3Br concentration → increases rate. Reducing OH^- concentration → decreases rate. Cooling → decreases rate (lower kinetic energy). Reducing pressure → negligible effect for liquid-phase reaction.

Explanation

1. Identify reaction type <br /> This is an SN2 reaction where rate depends on both $CH_3Br$ and $OH^-$. <br />2. Apply rate law <br /> **Rate = k[CH₃Br][OH⁻]** — increasing either concentration increases rate; decreasing either slows it. <br />3. Evaluate options <br /> Increasing $CH_3Br$ concentration → increases rate. <br /> Reducing $OH^-$ concentration → decreases rate. <br /> Cooling → decreases rate (lower kinetic energy). <br /> Reducing pressure → negligible effect for liquid-phase reaction.
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