QuestionJune 22, 2025

A gas is cooled from 365 K to 285 K while its volume changes from 12.8 Lto 9.9 L The initial pressure of the gas is 1.9 atm. What is the final pressure of the gas rounded to the nearest tenth? 1.3 atm 2.9 atm 1.9 atm 9.9 atm

A gas is cooled from 365 K to 285 K while its volume changes from 12.8 Lto 9.9 L The initial pressure of the gas is 1.9 atm. What is the final pressure of the gas rounded to the nearest tenth? 1.3 atm 2.9 atm 1.9 atm 9.9 atm
A gas is cooled from 365 K to 285 K while its volume
changes from 12.8 Lto 9.9 L The initial pressure of the
gas is 1.9 atm.
What is the final pressure of the gas rounded to the
nearest tenth?
1.3 atm
2.9 atm
1.9 atm
9.9 atm

Solution
4.7(202 votes)

Answer

2.5 atm Explanation 1. Apply Combined Gas Law Use the formula P_1 V_1 / T_1 = P_2 V_2 / T_2 to find P_2. 2. Substitute Known Values P_1 = 1.9 \, \text{atm}, V_1 = 12.8 \, \text{L}, T_1 = 365 \, \text{K}, V_2 = 9.9 \, \text{L}, T_2 = 285 \, \text{K}. 3. Solve for Final Pressure P_2 Rearrange to P_2 = P_1 \cdot (V_1/V_2) \cdot (T_2/T_1). Calculate: P_2 = 1.9 \cdot (12.8/9.9) \cdot (285/365). 4. Perform Calculation P_2 = 1.9 \cdot 1.2929 \cdot 0.7808 \approx 1.9 \cdot 1.009 \approx 2.5 \, \text{atm}.

Explanation

1. Apply Combined Gas Law<br /> Use the formula $P_1 V_1 / T_1 = P_2 V_2 / T_2$ to find $P_2$. <br /><br />2. Substitute Known Values<br /> $P_1 = 1.9 \, \text{atm}$, $V_1 = 12.8 \, \text{L}$, $T_1 = 365 \, \text{K}$, $V_2 = 9.9 \, \text{L}$, $T_2 = 285 \, \text{K}$.<br /><br />3. Solve for Final Pressure $P_2$<br /> Rearrange to $P_2 = P_1 \cdot (V_1/V_2) \cdot (T_2/T_1)$.<br /> Calculate: $P_2 = 1.9 \cdot (12.8/9.9) \cdot (285/365)$.<br /><br />4. Perform Calculation<br /> $P_2 = 1.9 \cdot 1.2929 \cdot 0.7808 \approx 1.9 \cdot 1.009 \approx 2.5 \, \text{atm}$.
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