QuestionAugust 25, 2025

Use the distance formula below to answer the question: d=sqrt ((x_(2)-x_(1))^2+(y_(2)-y_(1))^2) What is the distance between (7,-2) and (3,1) square

Use the distance formula below to answer the question: d=sqrt ((x_(2)-x_(1))^2+(y_(2)-y_(1))^2) What is the distance between (7,-2) and (3,1) square
Use the distance formula below to answer the question: d=sqrt ((x_(2)-x_(1))^2+(y_(2)-y_(1))^2) What is the distance between (7,-2) and (3,1) square

Solution
4.5(250 votes)

Answer

5 Explanation 1. Identify coordinates (x_1, y_1) = (7, -2) and (x_2, y_2) = (3, 1). 2. Apply distance formula Use d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}. Substitute values: d=\sqrt{(3-7)^2 + (1+2)^2}. 3. Calculate differences x_2 - x_1 = 3 - 7 = -4, y_2 - y_1 = 1 + 2 = 3. 4. Square differences (-4)^2 = 16, 3^2 = 9. 5. Sum squares 16 + 9 = 25. 6. Compute square root \sqrt{25} = 5.

Explanation

1. Identify coordinates<br /> $(x_1, y_1) = (7, -2)$ and $(x_2, y_2) = (3, 1)$.<br />2. Apply distance formula<br /> Use $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$.<br /> Substitute values: $d=\sqrt{(3-7)^2 + (1+2)^2}$.<br />3. Calculate differences<br /> $x_2 - x_1 = 3 - 7 = -4$, $y_2 - y_1 = 1 + 2 = 3$.<br />4. Square differences<br /> $(-4)^2 = 16$, $3^2 = 9$.<br />5. Sum squares<br /> $16 + 9 = 25$.<br />6. Compute square root<br /> $\sqrt{25} = 5$.
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