QuestionAugust 16, 2025

A solution is made by dissolving 42.3 g of potassium hydroxide in 329 g of water . What is the molality of the solution? KOH:56.11g/mol () m KOH

A solution is made by dissolving 42.3 g of potassium hydroxide in 329 g of water . What is the molality of the solution? KOH:56.11g/mol () m KOH
A solution is made by dissolving
42.3 g of potassium hydroxide in
329 g of water . What is the
molality of the solution?
KOH:56.11g/mol
() m KOH

Solution
4.0(258 votes)

Answer

2.29 \, \text{mol/kg} Explanation 1. Calculate moles of KOH Use the formula: \text{moles} = \frac{\text{mass}}{\text{molar mass}}. For KOH, \text{moles} = \frac{42.3 \, \text{g}}{56.11 \, \text{g/mol}}. 2. Convert water mass to kilograms Convert 329 g of water to kg: 329 \, \text{g} = 0.329 \, \text{kg}. 3. Calculate molality Molality (m) is calculated using: m = \frac{\text{moles of solute}}{\text{kilograms of solvent}}.

Explanation

1. Calculate moles of KOH<br /> Use the formula: $\text{moles} = \frac{\text{mass}}{\text{molar mass}}$. For KOH, $\text{moles} = \frac{42.3 \, \text{g}}{56.11 \, \text{g/mol}}$.<br />2. Convert water mass to kilograms<br /> Convert 329 g of water to kg: $329 \, \text{g} = 0.329 \, \text{kg}$.<br />3. Calculate molality<br /> Molality ($m$) is calculated using: $m = \frac{\text{moles of solute}}{\text{kilograms of solvent}}$.
Click to rate:

Similar Questions