QuestionJuly 20, 2025

How many grams of water are made from the reaction of 16.0 grams of oxygen gas? Given the reaction: 2H_(2)+O_(2)arrow 2H_(2)O 16 36 18 9 not enough information

How many grams of water are made from the reaction of 16.0 grams of oxygen gas? Given the reaction: 2H_(2)+O_(2)arrow 2H_(2)O 16 36 18 9 not enough information
How many grams of water are made from the reaction of 16.0 grams of oxygen gas?
Given the reaction: 2H_(2)+O_(2)arrow 2H_(2)O
16
36
18
9
not enough information

Solution
4.6(254 votes)

Answer

18 Explanation 1. Calculate moles of oxygen gas Molar mass of O_2 is 32 g/mol. Moles of O_2 = \frac{16.0 \text{ g}}{32 \text{ g/mol}} = 0.5 \text{ mol}. 2. Determine moles of water produced From the balanced equation, 1 mole of O_2 produces 2 moles of H_2O. Therefore, 0.5 moles of O_2 produce 0.5 \times 2 = 1 \text{ mol} of H_2O. 3. Calculate grams of water Molar mass of H_2O is 18 g/mol. Grams of H_2O = 1 \text{ mol} \times 18 \text{ g/mol} = 18 \text{ g}.

Explanation

1. Calculate moles of oxygen gas<br /> Molar mass of $O_2$ is 32 g/mol. Moles of $O_2 = \frac{16.0 \text{ g}}{32 \text{ g/mol}} = 0.5 \text{ mol}$.<br /><br />2. Determine moles of water produced<br /> From the balanced equation, 1 mole of $O_2$ produces 2 moles of $H_2O$. Therefore, 0.5 moles of $O_2$ produce $0.5 \times 2 = 1 \text{ mol}$ of $H_2O$.<br /><br />3. Calculate grams of water<br /> Molar mass of $H_2O$ is 18 g/mol. Grams of $H_2O = 1 \text{ mol} \times 18 \text{ g/mol} = 18 \text{ g}$.
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