QuestionAugust 23, 2025

Roberto invested a total of 10,000 part at 6% and part at 9% How much did he invest in the HIGHER interest account if the total interest earned in one year was 810 square

Roberto invested a total of 10,000 part at 6% and part at 9% How much did he invest in the HIGHER interest account if the total interest earned in one year was 810 square
Roberto invested a total of 10,000 part at 6%  and part at 9%  How much did he
invest in the HIGHER interest account if the total interest earned in one year was
 810
square

Solution
4.1(253 votes)

Answer

7000 Explanation 1. Define Variables Let x be the amount invested at 9\%. Then, 10000 - x is invested at 6\%. 2. Set Up Interest Equation Total interest from both investments is 0.06(10000 - x) + 0.09x = 810. 3. Simplify and Solve for x Simplify: 600 - 0.06x + 0.09x = 810. Combine terms: 0.03x = 210. Solve for x: x = \frac{210}{0.03} = 7000.

Explanation

1. Define Variables<br /> Let $x$ be the amount invested at $9\%$. Then, $10000 - x$ is invested at $6\%$.<br /><br />2. Set Up Interest Equation<br /> Total interest from both investments is $0.06(10000 - x) + 0.09x = 810$.<br /><br />3. Simplify and Solve for $x$<br /> Simplify: $600 - 0.06x + 0.09x = 810$. <br /> Combine terms: $0.03x = 210$. <br /> Solve for $x$: $x = \frac{210}{0.03} = 7000$.
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