QuestionApril 24, 2025

Consider the unbalanced reaction: As_(2)O_(3)(s)+NO_(3)^-(aq)arrow H_(3)AsO_(4)(aq)+NO(g) When balancing this equation, how many electrons are transferred? Enter your answer as a whole number. square

Consider the unbalanced reaction: As_(2)O_(3)(s)+NO_(3)^-(aq)arrow H_(3)AsO_(4)(aq)+NO(g) When balancing this equation, how many electrons are transferred? Enter your answer as a whole number. square
Consider the unbalanced reaction:
As_(2)O_(3)(s)+NO_(3)^-(aq)arrow H_(3)AsO_(4)(aq)+NO(g)
When balancing this equation, how many electrons are transferred?
Enter your answer as a whole number.
square

Solution
4.4(336 votes)

Answer

7 Explanation 1. Identify oxidation states of key elements In As_2O_3, arsenic (As) has an oxidation state of +3. In H_3AsO_4, arsenic changes to +5. Nitrogen in NO_3^- has an oxidation state of +5, and in NO, it changes to +2. 2. Calculate electron transfer for arsenic Each arsenic atom undergoes a change from +3 to +5, losing 2 electrons. Since there are 2 arsenic atoms, total electrons lost = 2 \times 2 = 4. 3. Calculate electron transfer for nitrogen Each nitrogen atom undergoes a change from +5 to +2, gaining 3 electrons. Total electrons gained = 3 \times 1 = 3. 4. Balance electron transfer To balance the reaction, the total number of electrons transferred is the sum of electrons lost and gained: 4 + 3 = 7.

Explanation

1. Identify oxidation states of key elements<br /> In $As_2O_3$, arsenic (As) has an oxidation state of +3. In $H_3AsO_4$, arsenic changes to +5. Nitrogen in $NO_3^-$ has an oxidation state of +5, and in $NO$, it changes to +2.<br /><br />2. Calculate electron transfer for arsenic<br /> Each arsenic atom undergoes a change from +3 to +5, losing 2 electrons. Since there are 2 arsenic atoms, total electrons lost = $2 \times 2 = 4$.<br /><br />3. Calculate electron transfer for nitrogen<br /> Each nitrogen atom undergoes a change from +5 to +2, gaining 3 electrons. Total electrons gained = $3 \times 1 = 3$.<br /><br />4. Balance electron transfer<br /> To balance the reaction, the total number of electrons transferred is the sum of electrons lost and gained: $4 + 3 = 7$.
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