QuestionApril 19, 2025

If 6.00 Lof H_(2)O gas at 50.2^circ C and a pressure of 0.12 atm reacts completely with Fe according to the balanced equation shown, what mass in grams of iron (III) oxide would be produced? 2Fe(s)+3H_(2)O(g)arrow Fe_(2)O_(3)(s)+3H_(2)(g) mass: square g

If 6.00 Lof H_(2)O gas at 50.2^circ C and a pressure of 0.12 atm reacts completely with Fe according to the balanced equation shown, what mass in grams of iron (III) oxide would be produced? 2Fe(s)+3H_(2)O(g)arrow Fe_(2)O_(3)(s)+3H_(2)(g) mass: square g
If 6.00 Lof H_(2)O gas at 50.2^circ C and a pressure of 0.12 atm reacts completely with Fe according to the balanced equation
shown, what mass in grams of iron (III) oxide would be produced?
2Fe(s)+3H_(2)O(g)arrow Fe_(2)O_(3)(s)+3H_(2)(g)
mass: square  g

Solution
4.7(293 votes)

Answer

1.485 g Explanation 1. Calculate moles of H_2O Use the ideal gas law: **PV = nRT**. Given P = 0.121 \, \text{atm}, V = 6.00 \, \text{L}, T = 50.2^{\circ}C = 323.35 \, \text{K}, and R = 0.0821 \, \text{L atm/mol K}. n = \frac{PV}{RT} = \frac{0.121 \times 6.00}{0.0821 \times 323.35} \approx 0.0279 \, \text{mol} 2. Determine moles of Fe_2O_3 produced From the balanced equation, 3 moles of H_2O produce 1 mole of Fe_2O_3. Thus, moles of Fe_2O_3 = \frac{0.0279}{3} \approx 0.0093 \, \text{mol}. 3. Calculate mass of Fe_2O_3 Molar mass of Fe_2O_3 = 159.69 \, \text{g/mol}. Mass = moles \times molar mass = 0.0093 \times 159.69 \approx 1.485 \, \text{g}.

Explanation

1. Calculate moles of $H_2O$<br /> Use the ideal gas law: **$PV = nRT$**. Given $P = 0.121 \, \text{atm}$, $V = 6.00 \, \text{L}$, $T = 50.2^{\circ}C = 323.35 \, \text{K}$, and $R = 0.0821 \, \text{L atm/mol K}$.<br /> $n = \frac{PV}{RT} = \frac{0.121 \times 6.00}{0.0821 \times 323.35} \approx 0.0279 \, \text{mol}$<br /><br />2. Determine moles of $Fe_2O_3$ produced<br /> From the balanced equation, 3 moles of $H_2O$ produce 1 mole of $Fe_2O_3$. Thus, moles of $Fe_2O_3 = \frac{0.0279}{3} \approx 0.0093 \, \text{mol}$.<br /><br />3. Calculate mass of $Fe_2O_3$<br /> Molar mass of $Fe_2O_3 = 159.69 \, \text{g/mol}$. Mass = moles $\times$ molar mass = $0.0093 \times 159.69 \approx 1.485 \, \text{g}$.
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