QuestionApril 28, 2025

Based on this same prompt, how many moles of the conjugate base have formed after 12.516 mL of the NaOH titrant was added? Write your answer to 3 significant figures.

Based on this same prompt, how many moles of the conjugate base have formed after 12.516 mL of the NaOH titrant was added? Write your answer to 3 significant figures.
Based on this same prompt, how many moles of the conjugate base have formed after
12.516 mL of the NaOH titrant was added?
Write your answer to 3 significant figures.

Solution
4.6(267 votes)

Answer

The moles of conjugate base formed are n = C \cdot 0.012516. Substitute the given concentration of NaOH to calculate the final value. Explanation 1. Calculate moles of NaOH added Use the formula n = C \cdot V, where C is the concentration of NaOH and V is the volume in liters. Convert 12.516 mL to liters: V = 12.516 \, \text{mL} \times \frac{1}{1000} = 0.012516 \, \text{L}. 2. Relate moles of NaOH to moles of conjugate base Since NaOH reacts 1:1 with the acid to form the conjugate base, the moles of NaOH added equal the moles of conjugate base formed.

Explanation

1. Calculate moles of NaOH added<br /> Use the formula $n = C \cdot V$, where $C$ is the concentration of NaOH and $V$ is the volume in liters. Convert 12.516 mL to liters: $V = 12.516 \, \text{mL} \times \frac{1}{1000} = 0.012516 \, \text{L}$.<br /><br />2. Relate moles of NaOH to moles of conjugate base<br /> Since NaOH reacts 1:1 with the acid to form the conjugate base, the moles of NaOH added equal the moles of conjugate base formed.
Click to rate:

Similar Questions