QuestionAugust 27, 2025

Determine the range of f(x)=vert xvert -4 yvert -infty lt ylt infty yvert -4leqslant ylt infty yvert 0lt ylt infty yvert 4lt ylt infty

Determine the range of f(x)=vert xvert -4 yvert -infty lt ylt infty yvert -4leqslant ylt infty yvert 0lt ylt infty yvert 4lt ylt infty
Determine the range of f(x)=vert xvert -4
 yvert -infty lt ylt infty 
 yvert -4leqslant ylt infty 
 yvert 0lt ylt infty 
 yvert 4lt ylt infty

Solution
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Answer

\{ y \mid -4 \leqslant y < \infty \} Explanation 1. Analyze the function The function f(x) = |x| - 4 involves an absolute value, which is always non-negative. Thus, |x| \geq 0 for all x. 2. Determine minimum value Since |x| \geq 0, the smallest value of f(x) occurs when |x| = 0. Therefore, f(x) = 0 - 4 = -4. 3. Determine range As |x| increases from 0 to \infty, f(x) = |x| - 4 increases from -4 to \infty. Hence, the range is [-4, \infty).

Explanation

1. Analyze the function<br /> The function $f(x) = |x| - 4$ involves an absolute value, which is always non-negative. Thus, $|x| \geq 0$ for all $x$.<br />2. Determine minimum value<br /> Since $|x| \geq 0$, the smallest value of $f(x)$ occurs when $|x| = 0$. Therefore, $f(x) = 0 - 4 = -4$.<br />3. Determine range<br /> As $|x|$ increases from 0 to $\infty$, $f(x) = |x| - 4$ increases from $-4$ to $\infty$. Hence, the range is $[-4, \infty)$.
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