QuestionJuly 25, 2025

The oxidation number of nitrogen given for all the following species is correct except: NH_(2)OH(-1) N_(2)H_(4)(-2) N_(2)O(+1) HNO_(2)(+3) HN_(3)(-1)

The oxidation number of nitrogen given for all the following species is correct except: NH_(2)OH(-1) N_(2)H_(4)(-2) N_(2)O(+1) HNO_(2)(+3) HN_(3)(-1)
The oxidation number of nitrogen given for all the following species is correct except:
NH_(2)OH(-1)
N_(2)H_(4)(-2)
N_(2)O(+1)
HNO_(2)(+3)
HN_(3)(-1)

Solution
3.6(271 votes)

Answer

HN_{3}(-1) is incorrect; the oxidation number of nitrogen should be -\frac{1}{3}. Explanation 1. Calculate Oxidation Number for NH_{2}OH Nitrogen in NH_{2}OH: Let oxidation number be x. 1(x) + 2(+1) + 1(-2) + 1(+1) = 0 \Rightarrow x = -1. 2. Calculate Oxidation Number for N_{2}H_{4} Nitrogen in N_{2}H_{4}: Let oxidation number be x. 2(x) + 4(+1) = 0 \Rightarrow x = -2. 3. Calculate Oxidation Number for N_{2}O Nitrogen in N_{2}O: Let oxidation number be x. 2(x) + 1(-2) = 0 \Rightarrow x = +1. 4. Calculate Oxidation Number for HNO_{2} Nitrogen in HNO_{2}: Let oxidation number be x. 1(+1) + 1(x) + 2(-2) = 0 \Rightarrow x = +3. 5. Calculate Oxidation Number for HN_{3} Nitrogen in HN_{3}: Let oxidation number be x. 1(+1) + 3(x) = 0 \Rightarrow x = -\frac{1}{3}.

Explanation

1. Calculate Oxidation Number for $NH_{2}OH$<br /> Nitrogen in $NH_{2}OH$: Let oxidation number be $x$. $1(x) + 2(+1) + 1(-2) + 1(+1) = 0 \Rightarrow x = -1$.<br />2. Calculate Oxidation Number for $N_{2}H_{4}$<br /> Nitrogen in $N_{2}H_{4}$: Let oxidation number be $x$. $2(x) + 4(+1) = 0 \Rightarrow x = -2$.<br />3. Calculate Oxidation Number for $N_{2}O$<br /> Nitrogen in $N_{2}O$: Let oxidation number be $x$. $2(x) + 1(-2) = 0 \Rightarrow x = +1$.<br />4. Calculate Oxidation Number for $HNO_{2}$<br /> Nitrogen in $HNO_{2}$: Let oxidation number be $x$. $1(+1) + 1(x) + 2(-2) = 0 \Rightarrow x = +3$.<br />5. Calculate Oxidation Number for $HN_{3}$<br /> Nitrogen in $HN_{3}$: Let oxidation number be $x$. $1(+1) + 3(x) = 0 \Rightarrow x = -\frac{1}{3}$.
Click to rate:

Similar Questions