QuestionMay 1, 2025

A student is using these conversion factors to convert from 2.5 grams of the given reactant to the mass of product. Identify any conversion factors that would NOT work. Tap to select or deselect an answer. Select all that would NOT work. 2Al+3CuCl_(2)arrow 2AlCl_(3)+3Cu 2.5gAltimes (1molAl)/(27.0gAl)times (3molCu)/(2molAl)times (63.5gCu)/(1molCu) Na_(2)O+H_(2)Oarrow 2NaOH 2.5gH_(2)Otimes (1molH_(2)O)/(18.0gH_(2)O)times (1gH_(2)O)/(2gNaOH)times (40.0gNaOH)/(1molNaOH) 2Cu+Sarrow Cu_(2)S 2.5gCutimes (1molCu)/(63.5gCu)times (2molCu_(2)S)/(1molCu)times (159.2gCu_(2)S)/(1molCu_(2)S)

A student is using these conversion factors to convert from 2.5 grams of the given reactant to the mass of product. Identify any conversion factors that would NOT work. Tap to select or deselect an answer. Select all that would NOT work. 2Al+3CuCl_(2)arrow 2AlCl_(3)+3Cu 2.5gAltimes (1molAl)/(27.0gAl)times (3molCu)/(2molAl)times (63.5gCu)/(1molCu) Na_(2)O+H_(2)Oarrow 2NaOH 2.5gH_(2)Otimes (1molH_(2)O)/(18.0gH_(2)O)times (1gH_(2)O)/(2gNaOH)times (40.0gNaOH)/(1molNaOH) 2Cu+Sarrow Cu_(2)S 2.5gCutimes (1molCu)/(63.5gCu)times (2molCu_(2)S)/(1molCu)times (159.2gCu_(2)S)/(1molCu_(2)S)
A student is using these conversion factors to convert from 2.5 grams of the given reactant to the mass of product. Identify any conversion factors that would NOT work. Tap to select or deselect an answer. Select all that would NOT work. 2Al+3CuCl_(2)arrow 2AlCl_(3)+3Cu 2.5gAltimes (1molAl)/(27.0gAl)times (3molCu)/(2molAl)times (63.5gCu)/(1molCu) Na_(2)O+H_(2)Oarrow 2NaOH 2.5gH_(2)Otimes (1molH_(2)O)/(18.0gH_(2)O)times (1gH_(2)O)/(2gNaOH)times (40.0gNaOH)/(1molNaOH) 2Cu+Sarrow Cu_(2)S 2.5gCutimes (1molCu)/(63.5gCu)times (2molCu_(2)S)/(1molCu)times (159.2gCu_(2)S)/(1molCu_(2)S)

Solution
4.2(166 votes)

Answer

The second and third conversion factors would NOT work. Explanation 1. Analyze the first conversion factor 2.5gAl \times \frac{1molAl}{27.0gAl} \times \frac{3molCu}{2molAl} \times \frac{63.5gCu}{1molCu} is correct. It uses the stoichiometry of the balanced equation 2Al + 3CuCl_{2} \rightarrow 2AlCl_{3} + 3Cu. 2. Analyze the second conversion factor 2.5gH_{2}O \times \frac{1molH_{2}O}{18.0gH_{2}O} \times \frac{1gH_{2}O}{2gNaOH} \times \frac{40.0gNaOH}{1molNaOH} is incorrect. The factor \frac{1gH_{2}O}{2gNaOH} is not a valid stoichiometric ratio from the equation Na_{2}O + H_{2}O \rightarrow 2NaOH. 3. Analyze the third conversion factor 2.5gCu \times \frac{1molCu}{63.5gCu} \times \frac{2molCu_{2}S}{1molCu} \times \frac{159.2gCu_{2}S}{1molCu_{2}S} is incorrect. The factor \frac{2molCu_{2}S}{1molCu} should be \frac{1molCu_{2}S}{2molCu} based on the equation 2Cu + S \rightarrow Cu_{2}S.

Explanation

1. Analyze the first conversion factor<br /> $2.5gAl \times \frac{1molAl}{27.0gAl} \times \frac{3molCu}{2molAl} \times \frac{63.5gCu}{1molCu}$ is correct. It uses the stoichiometry of the balanced equation $2Al + 3CuCl_{2} \rightarrow 2AlCl_{3} + 3Cu$.<br /><br />2. Analyze the second conversion factor<br /> $2.5gH_{2}O \times \frac{1molH_{2}O}{18.0gH_{2}O} \times \frac{1gH_{2}O}{2gNaOH} \times \frac{40.0gNaOH}{1molNaOH}$ is incorrect. The factor $\frac{1gH_{2}O}{2gNaOH}$ is not a valid stoichiometric ratio from the equation $Na_{2}O + H_{2}O \rightarrow 2NaOH$.<br /><br />3. Analyze the third conversion factor<br /> $2.5gCu \times \frac{1molCu}{63.5gCu} \times \frac{2molCu_{2}S}{1molCu} \times \frac{159.2gCu_{2}S}{1molCu_{2}S}$ is incorrect. The factor $\frac{2molCu_{2}S}{1molCu}$ should be $\frac{1molCu_{2}S}{2molCu}$ based on the equation $2Cu + S \rightarrow Cu_{2}S$.
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