QuestionMay 6, 2025

The value of Delta H^circ for the reaction below is -1107kJ 2Ba(s)+O_(2)(g)arrow 2BaO(s) How many kJ of heat are released when 575 g of Ba (s) reacts completely with oxygen to form BaO(s)? 96.3 kJ 46.4 kJ 26.3 kJ 23.2 kJ 193 kJ

The value of Delta H^circ for the reaction below is -1107kJ 2Ba(s)+O_(2)(g)arrow 2BaO(s) How many kJ of heat are released when 575 g of Ba (s) reacts completely with oxygen to form BaO(s)? 96.3 kJ 46.4 kJ 26.3 kJ 23.2 kJ 193 kJ
The value of Delta H^circ for the reaction below is -1107kJ 2Ba(s)+O_(2)(g)arrow 2BaO(s) How many kJ of heat are released when 575 g of Ba (s) reacts completely with oxygen to form BaO(s)? 96.3 kJ 46.4 kJ 26.3 kJ 23.2 kJ 193 kJ

Solution
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Answer

193 kJ Explanation 1. Calculate moles of Ba Molar mass of Ba is 137.33 g/mol. Moles of Ba = \frac{575 \text{ g}}{137.33 \text{ g/mol}}. 2. Determine heat released per mole Reaction releases -1107 \text{ kJ} for 2 moles of Ba. Heat per mole = \frac{-1107 \text{ kJ}}{2}. 3. Calculate total heat released Total heat = moles of Ba \times heat per mole.

Explanation

1. Calculate moles of Ba<br /> Molar mass of Ba is 137.33 g/mol. Moles of Ba = $\frac{575 \text{ g}}{137.33 \text{ g/mol}}$.<br />2. Determine heat released per mole<br /> Reaction releases $-1107 \text{ kJ}$ for 2 moles of Ba. Heat per mole = $\frac{-1107 \text{ kJ}}{2}$.<br />3. Calculate total heat released<br /> Total heat = moles of Ba $\times$ heat per mole.
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