QuestionAugust 26, 2025

Solve the following inequality algebraically. (3x-4)/(x+3)leqslant 2 What is the solution? square (Type your answer in interval notation. Simplify your answer. Use integers or fractions for any numbers in the expression.)

Solve the following inequality algebraically. (3x-4)/(x+3)leqslant 2 What is the solution? square (Type your answer in interval notation. Simplify your answer. Use integers or fractions for any numbers in the expression.)
Solve the following inequality algebraically.
(3x-4)/(x+3)leqslant 2
What is the solution?
square 
(Type your answer in interval notation. Simplify your answer. Use integers or fractions for any
numbers in the expression.)

Solution
4.4(301 votes)

Answer

(-\infty, -3) \cup (-3, 10] Explanation 1. Clear the Fraction Multiply both sides by (x+3), assuming x \neq -3: 3x - 4 \leq 2(x + 3). 2. Simplify the Inequality Expand and simplify: 3x - 4 \leq 2x + 6. 3. Isolate x Subtract 2x from both sides: x - 4 \leq 6. Add 4 to both sides: x \leq 10. 4. Consider Domain Restrictions The expression is undefined at x = -3. Thus, x \neq -3. 5. Combine Results Combine the inequality x \leq 10 with the domain restriction x \neq -3.

Explanation

1. Clear the Fraction<br /> Multiply both sides by $(x+3)$, assuming $x \neq -3$: $3x - 4 \leq 2(x + 3)$.<br /><br />2. Simplify the Inequality<br /> Expand and simplify: $3x - 4 \leq 2x + 6$.<br /><br />3. Isolate x<br /> Subtract $2x$ from both sides: $x - 4 \leq 6$.<br /> Add 4 to both sides: $x \leq 10$.<br /><br />4. Consider Domain Restrictions<br /> The expression is undefined at $x = -3$. Thus, $x \neq -3$.<br /><br />5. Combine Results<br /> Combine the inequality $x \leq 10$ with the domain restriction $x \neq -3$.
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